<p>This practice exercise is from Chemistry: The Central Science by Brown, Lemay, and Bursten on page 588. I can’t figure out how to get the answer.</p>
<p>The decomposition of dimethyl ether, (CH3)2O, at 510degsC is a first-order process with a rate constant of 6.8 x 10^-4 s^-1:</p>
<p>(CH3)2O (g) -----> CH4 (g) + H2 (g) + CO (g)</p>
<p>If the initial pressure of (CH3)2O is 135 torr, what is its partial pressure after 1420 s?</p>
<p>ANSWER: 51 torr</p>
<p>I thought about using the integrated rate law, but I’m not really sure how to incorporate pressure into it. Perhaps I am missing something?</p>