<li>Atom Y is in Group IIIA and atom Z is in Group VIA. A compound formed between these two elements would have the formula</li>
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<p>A. YZ2
B. Y2Z5
C. Y3Z2
D. Y2Z3
E. None of the above</p>
<p>Can someone explain this problem to me? My friend is trying to explain it to me, but I don’t understand him. Please make it really simple. Thanks.</p>
<p>answer is D</p>
<p>since Y is in group 3 it has 3 valence so it will go down beside the Z for Z3
since Z is in group 6 it has 2 valence so if will go down for Y2</p>
<p>hence: Y2Z3</p>
<p>i think</p>
<p>Since atom Y is in group 3, it has 3 valence electrons, and thus forms ions with charge 3+. By the same reasoning, atom Z has 6 valence electrons, and thus gains 2 electrons to form an ion of charge 2-. </p>
<p>A compound must have net charge zero, so we’re trying to find some combination of 3+'s and 2-'s to make 0. 2 3+'s and 3 2-'s make zero, so there are 2 Y atoms and 3 Z atoms, and the formula is Y2Z3.</p>
<p>LOL. Sorry guys. I misread the question. I thought atom Z was in Group IVA. But it was the other way around (VIA).</p>