<p>Hey, this is a precalculus question that I’m stuck on. It’s not for Math II, but I figured this would be the best place to ask it. Here goes:</p>
<p>In what quadrant does the terminal side of an angle of 10,560 (not a typo) degrees lie?</p>
<p>Prompt responses would be appreciated, as I have a test tomorrow. Thanks!</p>
<p>10560 degrees. Find the quadrant it lies in</p>
<p>Since 360 degrees is one rotation, 720 two rotations, etc, then find out how many rotations 10560 is.</p>
<p>10560/360 = 29.3333
so that means theres 29 complete rotations</p>
<p>so then you find out how many degrees 29 rotations are.
29*360 = 10440 degrees</p>
<p>subtract that from 10560
10560-10440 = 120</p>
<p>meaning once the terminal side of the angle goes around the plane 33 times, itll land in quadrant 2 (90 degrees - 180 degrees) at 120 degrees.</p>
<p>Sorry for taking so long to respond. But I really appreciate your help!</p>