<p>Which has the largest # of molecules: CuCl2…CS2…CH3Cl…C2H2F2</p>
<p>i think the answer is C2H2F2…but is this like a trick question, or is it just really really really easy?(I tend to over think a lot).</p>
<p>thanks for the help.</p>
<p>Are you in AP Chemistry? </p>
<p>First of all, are all those compounds 1 mole each?</p>
<p>If they are all 1 mole, then C2H2F2 is the largest molecule. </p>
<p>To calculate the number of molecules, multiply the amount of moles by 6.02 X 10^23. Then, multiply that by the number of atoms of each element.</p>
<p>For example, the number of atoms for H2O would e 3 because there are 2 Hydrogen atoms and 1 Oxygen atom.</p>
<p>1 mole of H2O would be multiplied by 6.02 X 10^23 and then, you would multiply it by 3. The answer would be the number of molecules.</p>
<p>^ thank you. I have another Q if you don’t mind:</p>
<p>how many orbitals (not electrons) are possible with the quantum numbers n=4 l=3 and ml=0?</p>
<p>there a 2 electrons, but how many orbitals?</p>
<p>anyone?..</p>
<p>please help :(</p>
<p>It depends…maybe if you wrote out the entire question, it would help. I can’t tell whether you are asking in terms of # of molecules in a certain weight, or the fact that CuCl2 will actually contribute 3 particles to water as the ions dissociate…</p>
<p>And while you would use Avagadro’s number (6.022 E23) to determine the number of molecules, you would NOT multiply it by 3 for H2O…that would determine the number of ATOMS, not MOLECULES. If you have one mol of H2O and one mol of O2, you still have the same # of molecules of each. </p>
<p>As for the second question, only one orbital is possible, because n determines the overall energy level, l determines the orbital shape, and ml determines the orientation…the only determination left is the electron spin, or ms, which is always either +1/2 or -1/2.</p>
<p>If you’re taking AP chem, I would recommend the Barron’s review book…it is good both for learning and and reviewing the material and it has useful practice tests.</p>
<p>^ yeah, I have Barron’s 2008 for AP chem. It is extremely helpful. Also, thanks for the help.</p>
<p>De nada…I took it last year, and it was ridiculously hard, so I figured I’d see what I could remember…</p>