Gruber's Math Workbook Problem

<p>I've been going through Grubers and so far it has been pretty good, a couple typos and mistakes in the key here and there, but I can mostly figure it out. </p>

<p>But I've been stuck on this geometry problem forever it seems like. Geometry is one of my weaker aspects of the math section, so I was wondering if someone could help me out.</p>

<p>It is in section 3-4 and in the workbook that is page 197. It is questions 18-20, find angle <'s y,x and z. </p>

<p>When I set the problem into algebraic functions, the variables always seem to cancel out. What am I doing wrong? I was doing so well in this section and I was happy because geo is probably my weakest subject. </p>

<p>Help???</p>

<p>Tomorrow I'll try to draw and scan a copy of the problem on graph paper because it would be nearly impossible for me to explain this problem with words if you don't have the triangles in front of you. </p>

<p>Thanks</p>

<p>can you post the questions?</p>

<p>It's a triangle with angles measures, so I was going to draw it on graph paper and scan it tomorrow for people who don't have Gruber's. </p>

<p>hell maybe I'll just do it now.</p>

<p>grubers</a> math picture by NDboy15_photos - Photobucket</p>

<p>ok here it is, you should be able to zoom in a little bit.</p>

<p>edit:
Shouldn't the other interior angle with 2y be given or at least have a variable to help you out?</p>

<p>you are right: all you can say is 2y=4x thus y=2x.</p>

<p>Ok, thanks. Must be a typo.</p>

<p>The answer they have in the back of the section makes sense, but I didn't know how they got there. </p>

<p>thanks, kind of frustrating, I spent a lot of time on it.</p>

<p>I checked the book. the answer they give is y=50. The only way to get this answer is to give the third angle in the ACD triangle as being equal to y. in that case you can find 2y+y=150 thus y=50, and find x=25 and z=80.
So, yes, I think there is a missing piece of information in the drawing</p>