<p>Has to be B. Looking at the orientation of the line, slope must be negative, leaving us with just A and B. Since the x coordinate is greater than the y coordinate (and the line is symmetric about the origin), y’-y < x’-x. Thus slope must be less then one as well, leaving us with B.</p>
<p>|p| > |r| and the slope of the line is (r-0)/(p-0) = r/p. Since the denominator is larger than the numerator, the slope will be a number less than 1. It’s already obvious from the graph that slope is negative, so we’re looking for a slope between -1 and 0. The only choice that falls in that range is B.</p>
<p>Uhh it’s not that hard compared to others IMO. You know the is has to go farther left or right than it does up or down which means the slope has to be less than -1 which in this case, -.5 is the only choice that fits</p>
<p>The reason why it’s hard is becuase the SAT tests how well you can look at small pictures. It took me a good time to notice that it actually crosses at 0,0. </p>
<p>Only -2 and -1\2 work, but -2 means that |p|< |r|, so only -1\2 works.</p>
<p>This is why I hate the SAT math compared to the ACT. Instead of testing your mathmatical knowledge, it tests how well you can notice small details. If that were an ACT question, it would have specifically said it crossed through the point (0,0).</p>
<p>guys Im sorry if i didnt specify. I wanted this thread to die. It was on the 2nd page and you guys kept bringing it back. Basically, I gave you guys the wrong link ergo the wrong problem and i couldnt edit it back. I made a new thread with the right link</p>
<p>really? i thought it was easier. hmmm lemme take it look… i havent bothered to read the explanations and stuff… anyhow thanks for every1 for helping so generously. and shame on the people yelling at me that its really easy and fail to answer the question</p>