help me with this math question !!

Test Preparation
1

<p><a href=“http://i41.■■■■■■■.com/293fyx3.png[/url]”>http://i41.■■■■■■■.com/293fyx3.png&lt;/a&gt;
Line l intersects segment line A C at point B, as shown above. A point P on segment line A C is to be chosen at random. What is the probability that segment P C will intersect line l?</p>

<p>(A) 5 over 6
(B) 2 over 3
(C) 3 over 5
(D) 1 over 2
(E) 2 over 5</p>

2

<p>Hmm shouldn’t it be 3/5? Thing with P is that it either has to be at point A, middle of AB, or at B to intersect line l.</p>

3

<p>In order for line PC to intersect line l, line PC must be equal to or longer than line BC. So, basically point P needs to be between points A and B, including points A and B themselves. Since, the distance between A and B (2) is only a fraction of the total length of AC (5), then the probablity of Point P being between points A and B would be 2/5, the length of AB (where the point P must be at to satisfy the condition) over the total length of AC (the possible points where P could be placed at).</p>

<p>Remember the formula for probabilty:
P = number of wanted events/number of total events</p>

<p>The answer would be 3/5 if it was asking for the probability that segment AP will intersect line l.</p>

<p>Does that make sense?</p>

4

<p>Yea I get it. Just having a brain fart here…</p>

5

<p>^No sweat. I have those all the time, haha.</p>

6

<p>2/5 - if 3/5 then P is moving from B to C (BC = 3/5 AC) and PC will not intersect l</p>