<p>Hey everyone,</p>
<p>This is a problem that’s really been stumping me (taken from current ed. blue book, page 527, #6)</p>
<p>If x does not = 0 and x is inversely proportional to y, which of the following is directly proportional to 1/(x^2)?</p>
<p>(A) -1/(y^2)
(B) 1/(y^2)
(C) 1/y
(D) y
(E) y^2</p>
<p>I’m having some trouble figuring out the relation between the two proportions, inverse and direct. Thoughts, anyone?</p>
<p>I will give you a hint. The relationship x is inversely proportional to y, means that </p>
<p>x = k/y</p>
<p>where k is some constant. </p>
<p>Take this expression for x and substitute it in 1/x^2, it will tell you what 1/x^2 is proportional to. </p>
<p>You may have seen this type of a relationship in physics. The electrostatic force of attraction between two charges is inversely proportional to the square of the distance between the charges. </p>
<p>Force = k/d^2, where d is the distance between between the two charges.</p>
<p>So is it E?</p>
<p>Yes, the correct answer is E.</p>