<p>Major brain fart…I think it’s 200…but how do you get the answer in an easier way?</p>
<p>A pack of baseball cards costs $3, and a pack of hockey cards costs $1. A collector spent $300 dollars buying only packs of baseball and hockey cards. If he bought three times as many packs of hockey cards as packs of baseball cards, how many packs of cards did he buy altogether?</p>
<p>Let number of baseball packs be X.
Let number of hockey packs be Y.
3X + Y = 300
3X = Y
2Y = 300
Y = 150
3X = 150
X = 50
You are looking for X + Y, which is 200. Problem solved.</p>
<p>just set up a system of equations</p>
<p>we’ll call the number of baseball cards B and the number of hockey cards H.</p>
<p>$3(B)+$1(H)=$300
3B=H (since there were 3x as many hockey cards)</p>
<p>Plug the second equation into the first $3(B)+$1(3B)=$300
6B=300
B=50 (so he bought 50 packs of baseball cards)</p>
<p>finally plug the number of baseball cards into 3B=H so 3(50)=H and H=150
just add them together and you get 200 packs of cards</p>
<p>i mean how did you do, just curious. sys of equaitons is def the easiest way.</p>