<p>Amandeep1: this could be interesting because I don’t have my calculator with me right now. I might be able to walk you through it, but you are going to have to do the calculations!</p>
<p>When dealing with logs,subtraction indicates division. So:</p>
<p>log(z) - log(4) = log(z)/log(4)
log(z)/log(4) = 2
log(z) = 2log(4)
log (z) = (the solution to 2log(4))
When there is no base indicated, a base of 10 is inferred. So:
log “base 10” of z = the solution to 2log(4)
10^the solution should (hypothetically) = z </p>
<p>And you can always check your answer by plugging it into the original equation.</p>
<p>I haven’t done precalc/algebra II since school let out. I am a little rusty, but see if the above works!!</p>
<p>When I condensed the original problem to the inferred division problem, my method gives the right answer when I plugged my answer back into the division problem. could someone tell me if I am doing this right or not?</p>
<p>Both questions are beyond the SAT Reasoning test scope - they belong to the SAT Subject Math test.
log(z)-log(4) = log(z/4), so
log(z/4) = 2
10^log(z/4) = 10^2
z/4 = 100
z = 400</p>