is the june curve going to be similar to the january curve?

Test Preparation SAT Preparation
1

<p>is the june curve going to be similar to the january curve?</p>

2

<p>I’m not saying yes and I’m not saying no :slight_smile:
Maybe…hopefully it will be easier</p>

3

<p>not for math…that’s REALLY unlikely -_-</p>

4

<p>so u think thw mathcurve is going to be hard?..i hope its really easy</p>

5

<p>I think the math is not very easy, but not very hard. The grid-in for the f(1)=f(9)=12 one is gonna kill many people. Well, I guessed and I was right. yay.</p>

6

<p>i dont think i had that question</p>

7

<p>Did you have the question that was grid-in and the answer was 3?</p>

8

<p>hoganwan
answer could be either 3 or 7 right?</p>

9

<p>yeah, 3 or 7</p>

10

<p>yes!!!
lol
i’m so happy</p>

<p>but i’m mad that i got that president 9 terms thing
the answer is 1983 but i put 1982.</p>

<p>What did you get for the number line question?
A+B=-1, then C= something like that
i got 1…</p>

11

<p>I forget… anyway, it’s done.</p>

12

<p>I don’t it’ll be hard, but it’ll be may’s curve</p>

13

<p>which was the grid in with 3</p>

14

<ol>
<li><p>Yes, what was the grid-in with 3. Somebody tell us!</p></li>
<li><p>The curve will be average, I believe. Although many of the questions on that test were indeed easy, there were a lot that seemed easy, but many tripped up on (putting 96 for the vol of the open box, for instance).</p></li>
</ol>

15

<p>what was the answer for 3!!!</p>

16

<p>The last question for the grid-in!!! </p>

<p>Finding the root based on the followings:</p>

<p>f(1)=f(9)=12
vertex=(5,-4)</p>

<p>REMEMBER THIS QUESTION?!! this was with a graph(which was a really good tool to guess, coz it was exactly where the root were!)</p>

<p>Wait, do we have different test?</p>

17

<p>Wooo, I’m so glad the second grid-in ended being real. I could still get 800… Anyhow, the math is:</p>

<p>y=x^2+bx+c</p>

<p>Here you could’ve plugged in the variables and substituted one of the resulting two equations into the other. Or, remember the formula of h and solve:</p>

<p>h=-b/2a, where h is the x-coordinate of the vertex (h,k)
=> 5=-b/2 => -10=b
=> 12=(1)^2-10(1)+c => 12-1+10=c => c=21
Then, factor x^2-10x+21 into (x-7)(x-3) and set = to 0 for the roots.
Thus the answers, 3 and 7.</p>

<p>Why the hell did I do this?</p>

18

<p>Why did I just get one grid-in?!!!</p>

19

<p>different test… relax lol</p>