<p>Hi! I was doing a QAS test, and I came across a really interesting question. I got the answer wrong, so I was wondering if anyone could give me the right answer and an explanation! Any help would be welcome </p>
<p>In a series of integers X, Y, and W, the following is true: X is twice Y, and Y is one-third of W. What is the ratio of (w^2) to (x^2)?</p>
<p>Thank you!</p>
<p>Is the answer 9/4?</p>
<p>Yes it is. Why is it not 4/9?</p>
<p>btw whats QAS?</p>
<p>In a series of integers X, Y, and W, the following is true: x is twice y, and y is one-third of w. What is the ratio of (w^2) to (x^2)?</p>
<p>Let’s choose a value for w, say w=3 (why did I choose 3?). Then y=1/3 of w = 1, and x=2y=2.</p>
<p>So, w^2/x^2 = 3^2/2^2=9/4</p>
<p>Here’s an algebraic solution also (although I wouldn’t do it this way on the test unless your algebra skills are really sharp):</p>
<p>y=w/3, x=2y=2w/3. So w^2/x^2= w^2/(2w/3)^2 = w^2/[(4/9)w^2] = 1/(4/9) = 9/4.</p>
<p>uhh just plug in numbers cuz the algebraic way to do it during a test can slow you down a bit. Plug in 12 for x, 6 for y and then 18 for z. (X is twice y, and y is 1/3 of 18, that’s why). Then just take ur calc, and see what 18^2 is and what 12^2 is. Then u end up with 9/4.</p>