June 2008- Math Level 2

<p>The trough one you could use A = 1/2 ab sin C, plugging in 1.5 for a and b and theta for C.</p>

<p>For the surface area one, I visualized folding it and you’ll see that two sides of the triangular bases correspond to sides of the rectangles. You then use the pythagorean theorem to get the third side.</p>

<p>Three rectangles, two triangles.</p>

<p>Actually i didn’t get an exact answer for the SA one i just picked the answer closest to my approximation.</p>

<p>wasn’t 18 sin (theta) the answer for the volume one though?</p>

<p>18 sin theta is what I got.</p>

<p>I did that. The third side was sqrt33 (5.744). So the middle rectangular region is 8(7+5.744+4) and the two triangles together are 28. That adds up to 162, which wasn’t one of the choices.</p>

<p>the two triangles are 23…are they not?</p>

<p>I’m not sure, but didn’t the triangle have a base of 4 and a height of sqrt 33? So the two together would be 22.98, not 28. That’s where you probably went wrong. 28-22.98 is about 5 and your answer is off from 157 by 5.</p>

<p>Oooh, I did multiply it by 7 instead of 5.744. Rats.</p>

<p>anyone know what the choices were for the SA one? I’m kind of worried about that question now…</p>

<p>Correct answer was either C or D, can’t remember.</p>

<p>is there a chatroom to discuss this?</p>

<p>basically for the sa one it ended up being 12 times sqrt33 +88</p>

<p>What was #49, I don’t remember the question specifically</p>

<p>it’s the m^91+2m^90 = perfect square
what could m be</p>

<p>Can anybody explain why it is square root of 33?</p>

<p>oh yeah i put 34, cus 34 +2=36, which is a perfect square. (6)</p>

<p>Answer is 34^</p>

<p>^its sqrt of 33 since it is 7^2-4^2.(you are solving for the side of the rectangle)</p>

<p>based on what you guys know about this test and other tests what are you guys predicting the curve will look like this year for an 800?</p>

<p>oops 2 omitt 1 wrong so far</p>

<p>eek</p>

<p>k at least i got all the ones people have talked about that i didnt skip right so far…</p>