<p>The trough one you could use A = 1/2 ab sin C, plugging in 1.5 for a and b and theta for C.</p>
<p>For the surface area one, I visualized folding it and you’ll see that two sides of the triangular bases correspond to sides of the rectangles. You then use the pythagorean theorem to get the third side.</p>
<p>I did that. The third side was sqrt33 (5.744). So the middle rectangular region is 8(7+5.744+4) and the two triangles together are 28. That adds up to 162, which wasn’t one of the choices.</p>
<p>I’m not sure, but didn’t the triangle have a base of 4 and a height of sqrt 33? So the two together would be 22.98, not 28. That’s where you probably went wrong. 28-22.98 is about 5 and your answer is off from 157 by 5.</p>