<p>What as the answer to the x^30y problem and how do you do it?</p>
<p>^^^ i just plugged stuff in, i made x = 2 and y = 3 and spent a while fooling with the calculator, and something worked</p>
<p>i am pretty positive its 64a^6</p>
<p>if i’m wrong someone correct me</p>
<p>*unfortunately that wasted a lot of time :X</p>
<p>All I can say is, this test was almost the same as a Barron’s test. Down to the exact question types.
I would have utterly failed this without Barron’s.</p>
<p>haha i didn’t do any practice ='[</p>
<p>That’s what I got. But I did it a different way. I think it was something like x^(5y) = 2a. So then in order for x6(5y) to equal x^(30y), you have to multiply x^(5y) by x^6. And if you do that, you have to do it to the other side too which makes (2a)^6…which equals: 64a^6.</p>
<p>x^30y is same as x^5y * x^5y * x^5y * x^5y * x^5y * x^5y
x^5y = 2a
so…(2a)^6 = 64a^6</p>
<p>wish i’d thought of that :)</p>
<p>i forgot everything from precalc since i haven’t looked at it at all since last year… so the ones i left blank were standard deviation, polar coordinates, some other 1. i saw the limit problem and was like, YAY something that looks familiar… :D</p>
<p>was the vector one the only thing that had the vector in the 4th quaddrant (pointing down and to the right)?
i don’t technically remmber vectors but i think that worked</p>
<p>What was the answer for the question that said something like:
If you take ten consecutive numbers then:
I. the mean is equal to the median
II. the median is equal to the something
III. and something else</p>
<p>and then the answers were combinations of the roman numerals. What was it? Does anyone remember?</p>
<p>was 34 the answer to the m problem?</p>
<p>i figured that 34^1 + 2(34)^0 would be 36. rad36 = 6. i thought what the hell, 34^1 is basically 34^91 and 34^0 is basically 34^90 so i marked that =)</p>
<p>Revolution13, it was II only i think,</p>
<p>So what do you guys think the curve is for this test? I left 2 blank (23 and 49), and definitely got 1 wrong. I’m hoping for an 800…</p>
<p>what was the determinant one? i could get that matrix to compute in my calculator so i omitted it along with the add5, subtract 5, multiply by 5 problem</p>
<p>The determinant was 0. I did it on my calculator(TI-89s Rock!). Took a while, but doing Cramer’s Rule by hand is a pain.</p>
<p>LoL I totally randomly guessed 64a6. =D</p>
<p>Carsonne, really? I know that the “III” option asked about the mode…which was wrong. But I put that both I and II were true. Ughhh</p>
<p>And what about the “given f^-1(x) = root(x+something), for what value of x will f(x) = 5” question?</p>
<p>A) 0</p>
<p>message too short</p>
<p>revolution13, i think it was only “mean = median”</p>
<p>the det one…i was only 50% sure that the way i was doing it (cramer’s rule) was the right way but it turned out okay :)</p>
<p>Oh man, I guess I got that one wrong then. =/</p>
<p>Wait, 0 was the answer to the f^-1(x) f(5)?</p>
<p>yo wat was the probability one? x= # 1-10 and y= # 1-20 wat chance = odd or something.</p>