June 2010: Math II

<p>anyone get the answer for the recursively defined series</p>

<p>a(n)=1.05a(n-1) a(100)=something </p>

<p>what does a(10)=</p>

<p>I did on my calculator, I set the first term to 0 and got 163</p>

<p>Huh, I could’ve sworn it said from the edge of the disk. I don’t know, maybe you’re right.</p>

<p>I dunno, can anyone else help?</p>

<p>a(10) was 155</p>

<p>OK IM gonna prove to you guys the Laser question is D, 1036.</p>

<p>Using tangent.
You have, the radius of the disk is 50 ft,
the distance from the center of disk to earth’s laser emitting point is 225*5280=1188000
now, you want the angle of the triangle,
which is arc tan(50/1188000) = .0024114385
the error was .05degrees,
so you add .05 degrees to the angle, because the angle should get bigger to miss the disk.
so you get .0524114385
now to find the distance from the center of the disk to the point the laser ends, you get tan(.0524113385)=x/1188000 =1086.72
subtract 50ft, to get from edge of disk.
you get 1036.72. ft
which. is. D.</p>

<p>any disagreements?</p>

<p>techinically, the triangle formed, is a right triangle, one leg being 50ft, the other leg being 1188000. the angle of .0024114385 is formed between the hypotenuse and the leg 1188000.
the angle increases to .0524114385, and you get a new leg, instead of 50ft, of 1086.7 ft.
subtract 50. you get 1036.7.</p>

<p>Wouldn’t you add the 0.05 degree error from earth to center of circle since the scientist was aiming at the center? Making the angle of the triangle 0.05 degrees.</p>

<p>plus for the laser one u can use law of sine</p>

<p>which is much easier…</p>

<p>i took it but i just realized i didnt re-write the oath at the bottom
after taking the test. i didn’t kno i was supposed to , so i just signed my name!
will my score be considered invalid and cancled? :frowning: urgh i thought i did good</p>

<p>did anyone get “not enough info” for the equilateral triangle?</p>

<p>and does anybody remember if the point (8,12) was “C?”</p>

<p>whatisthis-</p>

<p>That is what I was trying to explain. I believe you are correct.</p>

<p>Nope, you were given two points, so you can find the length of a side (5 i think), then just multiply by three.</p>

<p>for the perimeter of equilateral it was 15</p>

<p>Ffffffffff there was another agreement at the bottom of the 2nd test too? I forgot to sign that, our instructor didn’t tell us to; she just told us to close our answer sheets and turn them in.</p>

<p>For the parametric one, I’m pretty sure the correct answer is -1/3, not 1/3. After you eliminate the parameter, you get that it intersects the y axis at -1/3.</p>

<p>^yeah the answer was definitely negative.</p>

<p>do you guys remember if the ratio one (1:2) for the one where the side was root13 was “C?”</p>

<p>@biodudeyay you just reminded me. How many times are you supposed to sign the oath? once per subject or once for the entire thing?</p>

<p>Mullin-
There was only one on my answer sheet.</p>

<p>@Bball it was (8,12)</p>