<p>But I graphed it in my calculator and it came out around .7/.8 and that was an answer choice…</p>
<p>How was your window? Plug in 0.0001^0.0001 if you don’t believe me</p>
<p>@connie</p>
<p>Try 0.00001^0.00001, you get 0.999xxx</p>
<p>Graph “lnx” and “e^-x”, find the intersection point</p>
<p>Hypotonuse is 1 (radius of unit circle). Sin is o/h, o is half the entire chord (two identical triangles). sin(theta) is o/h=o/1=o. Multiply by two to get the entire length of the chord.
sin2theta doesn’t make any sense since it wouldn’t be a right triangle anymore.</p>
<p>2 and 3. (n)(n+1)(n+2), at least one of these numbers is even, so it is divisible by two. At least one of these number is a multiple of three, divisible by three. But it doesn’t have to be a multiple of four (5,6,7).</p>
<p>Probably 780, no idea though</p>
<p>whoops. that question might’ve been from a practice test. Sorry!
And how would the minimum be three if they can only give integral scores?</p>
<p>Ughhh nooo I need an 800…</p>
<p>can anyone explain the cone question to me? (18.88)
okay i remember the radius was 2, and the height was 3?</p>
<p>so V= 1/3 (pi) (r^2)(h)
= (1/3)pi (4)(3)
= 4pi
= 12.57?</p>
<p>I don’t remember the exact numbers, but I know for sure that it was 18.88. it would have been 12.57 had been rotated around the y-axis instead of the x-axis.</p>
<p>r was 3 h was 2</p>
<p>im so sad i missed 3 of the easiest ones T.T symmetry, radian (eff my mind slipped and told me pi was 90), and the x>=3 one ahhhhhh</p>
<p>are you sure??
the triangle looked exactly like this:
/|
/ |
/ |
/__|</p>
<p>yea im 100% sure do it. pi(9)(2) / 3 = 18.84955592</p>
<p>yes, the radius was definitely 3 and the height was 2</p>
<p>2 years of calc and i forgot what “with respect to” meant ■■■</p>
<p>i agree with wootSAT, the radius was definitely 2 and the height was 3, therefore the volume=(1/3)pie rsquared h. i got somewhere aroud 12 as well, not sure where 18 came from</p>
<p>Yeah, I got radius 3 and height 2 as well. We are all referring to the radius as the top part of the length of the cone right?</p>
<p>i’m sorry for being so annoying guys, but i can’t remember two of the answers I put and it’s bugging me…</p>
<p>For the ratio one (1:2), was the answer C? i know it was (8,12), but was that “C?”</p>
<p>And for the parametric one i was almost positive i got it right, but was -1/3 “D?”</p>
<p>@basketball, it was rotated around the X-axis, not the Y-axis. There for what you thought was height would actually be the radius.</p>
<p>u guys are aware that height is the x-axis between where the base (right side) of the triangle touched the x axis at (2,0) rite? vertex of the triangle was at (2,3)</p>
<p>Anyone with the law of sines problem???</p>
<p>think it was like 15.62</p>