<p>okay i am freaking out. i was getting 750s on barrons and i do sparknotes and im getting like 710-720 WTH… omg are the sparknotes questions the same difficulty as CB or harder? omg i need that 800.</p>
<p>how is 6. E… i think its D.</p>
<p>and 2. b 3. E.</p>
<p>guyss-540 on barrons just now…am i screwed? been getting 690s on sparknotes, 740 on cb</p>
<p>wth really? sparknotes really that easy? i find it so much more difficult? maybe its cause im doing tests on a computer.</p>
<p>3 is E my bad.</p>
<p>@NSpired And for 6, I think I’d the plane would “slice” a corner, it could form a triangle.</p>
<ol>
<li><p>E. The intersection can form a square (obviously) and a triangle (by cutting of a corner). What most people miss is the fact that it can form a rectangle, if it is cut at an angle to one side but parallel to the other perpendicular side. This is because the length of one side is still the length of the cube, but the length of the other side of the quadrilateral will be a little bit longer because it is a diagonal on the face of a cube. A rectangle, of course, is a parallelogram, so the answer is E. </p></li>
<li><p>B. This is pretty straightforward in my opinion. It deals with the fact that a point on the perpendicular bisector of a segment will always be equidistant from the endpoints of the segment being perpendicularly bisected. </p></li>
<li><p>E. If x^2 = y^2, then both x and -x could equal y or -y in any combination, which contradicts the rest of the statement that strictly x = y. Therefore, E is false, and also the correct answer.</p></li>
</ol>
<p>gah iPod typo… ***if not I’d</p>
<p>Education, i see i completely disregarded the fact that a rectange is a parralelogram… you don’t even have to cut it at an angle. just cut it down the middle of the length and you get 2 perfect slabs of rectangles.</p>
<p>@EducationOD: can you draw me a picture for number 6? I’m kind of lost? (I don’t get teh triangle or parallelogram part at all). And for 17, yeah, I see that now… I drew my picture wrong on the paper (I plotted 4,0 instead of 0,4… silly me).</p>
<p>Also: can anyone explain basic logic stuff needed on SATII and how to tackle questions about intersections, rotations, etc.?</p>
<p>and im get 700s only on Sparkntes and i was getting 750s on barron wth is this!!? i need that 800…</p>
<p>and question
40. In an arithmetic sequence, a5 = a10 – 3 and a3 = –2. Between which two consecutive terms does 0 lie?</p>
<p>a6 and a7?</p>
<p>yeah how… gah i hate sparknotes tests…</p>
<p>Can someone let me know how I’m doing on these and what I should be expecting come Saturday, score-wise? </p>
<p>Barron’s Model Test 1: 30.25 (663)</p>
<p>Barron’s Model Test 2: 39.5 (760)</p>
<p>Barron’s Model Test 3: 33.75 (700)</p>
<p>Barron’s Model Test 4: 34.75 (710)</p>
<p>Is a square not a parallelogram either?</p>
<p>Sparknotes seemed harder than Barrons for some reason i got middle 700’s in barrons then upper 600’s on the first sparknotes test. maybe it is just staring at a computer rather than a paper test. should i just rely on barrons then???</p>
<p>ya idk how ppl do the sparknotes, lol
i literally have to have a notebook out and write out the question and it takes up half the timee</p>
<p>i got up to like question 17 on the sparknotes and i just stopped</p>
<p>Umm, I don’t think I can draw a picture, because I’m a little caught up in studying for bio… But this should help. I think this is what Nspired was getting it.</p>
<p>So, instead of my complicated way, just picture this. One side of the rectangle can be any edge. The other side can be either the edge on the same face, or the edge diagonal to the first one. If you pick the edge on the same face, connect the dots, and you just get a square… If you pick the edge that’s diagonal, you connect the dots and you get a rectangle. So in the picture below, just connect the two red edges and you get a rectangle. That cube is evidence of HTML black magic. :)</p>
<p>…____<strong><em>
…/…/|<br>
./</em></strong><strong><em>/.|
|…|…|
|…|…|
|…|./
|**</em></strong>__**|/</p>
<p>And for the arithmetic series question, just set the first term (a1) equal to a. Then a5 = a + 4d (where d is the common difference) and a5 = a + 9d - 3. Set these equal and you get 4d = 9d - 3 and then d = 3/5. Now just keep adding 3/5 to -2 until you get a positive number, and figure out where between what two values that occurs.</p>
<p>@talib thats what i tried doing then i just got frustrated looking back and forth between the computer and paper and then stopped</p>