<p>“if a hexahedral die is rolled 2 times, what is the probability of not rolling a 6 both times”</p>
<p>how is it 25/36</p>
<p>the chance of it rolling 6 two times is 2 out of 36
so the chancer should be
34/36</p>
<p>…no?</p>
<p>That is poorly worded, I believe it means, "What is the probability of not rolling 6 on either roll, which makes sense as that would be (5/6)^2 = 25/36.</p>
<p>Is that an actual CB question?</p>
<p>yes, very poorly worded.</p>
<p>Probability of NOT rolling a 6 on the second time…</p>
<p>So there is a 5/6 chance you will not roll a 6. (5/6)^2 = 25/36</p>
<p>Short Way:
</h2>
<p>Long and Explained Way:
The question asks what are the chances in both independent rolls will you not role one six? All the combinations typed out may help you realize why the answer is 25/36.</p>
<p>All the combinations:
</p>
<p>(Total Combinations - Combinations with 6s in them)/36
(36 - 11) = 25/36</p>
<p>Rolling a 6 one time is not taken into consideration though, therefore, 34/36 is incorrect. 5/6 x 5/6 = 25/36.</p>
<p>Old thread is old.</p>