LOGICAL PROOF that test2's(korean mothers) experimental was about cows

<p>This is the test with korean mothers, gardening, privacy/technology…
I had 4 reading sections;1 is experimental
The first two sections were both 24 questions each=48 q’s</p>

<p>Section 6 (the experimental- pairpassage about nature/how children never saw cows) had 23 questions. 23!
Last reading section had 19 q’s, also a paired passage</p>

<p>Since a CR portion of the test cannot have more than 67 raw points, and ONE of the paired passage sections had to be experimental, logic tells us that section 6 was experimental.</p>

<p>oh and for this same test2 whatd you guys get for this math fill in? 27 players, with a chart with the number of points they got and one person 86. 1636? my friend is telling me different by saying that the question said 27 players and 27 DIFFERENT SCORES, which changes the answer completely</p>

<p>and i hope -1 isnt 760 like last month…</p>

<p>ANDDDD hahaha for grammar, whats the answ. to these?

  1. Fraternal twins are not always of the same sex and need not resemble each other more than any other two offspring of the same parents typically do. </p>

<li>The editor of the newspaper has asked maria and me to finish our article quickly so that it can be published in next week’s issue.</li>
</ol>

<p>i got 1611</p>

<p>1636 was the answer. check the math thread in this forum.</p>

<p>but i distinctly remember “27” being written twice. 27 players and 27 DIFFERENT scores? or just 27 scores? i edited my post btw</p>

<p>Okay.
27 players.</p>

<p>what is the MAXIMUM TOTAL SCORE THAT ALL 27 COMBINED PLAYERS CAN HAVE.</p>

<p>never said “distinct”</p>

<p>they give you “one player scored 86.”</p>

<p>add up MAX for each subgroup, and the last subgroup add 86 to 2(100).
your total= 1636</p>

<p>For the Grammer
I put E for fraternal and E for the second.</p>

<p>^ i put 2 e’s as well.</p>

<p>the “and me” in this case makes sense.</p>

<h1>1 and #2 I put D and B. Because any other two offspring of the same parents just sounds completely absurd. It’s a double-negative I believe.</h1>

<p>And…never, ever make the mistake of using something and “me”. It is always <other person=“”> and I. Just think of it in Spanish: “Maria y yo”</other></p>

<p>Obstinate: </p>

<p>That’s true only if the “<other person=”“> and I” are acting as the subjects of the sentence. In this case, however, “Maria and me” are acting as direct objects so “me” would be correct. Try taking out Maria: “The editor of the newspaper has asked I to finish…” wouldn’t make sense. It should be “me.”</other></p>

<p>if only you could apply the standards of Spanish to English.</p>

<p>No wonder English is so difficult to learn for many.</p>

<p>not true , obstinate. the following sentence is perfectly fine: </p>

<p>Jane and I are going to the store.</p>

<p>but</p>

<p>The man gave the test to Jane and I. [“me” makes clearer sense.]</p>

<p>concur with stepphen: (E) for the fraternal twins one. collegeboard often puts up very complex sentences such as those in order to make you think there is an error, but there is actually not.</p>

<p>I can’t remember what i got on the grid in with the 27 players, however, tell me if this was right. it was something like…</p>

<p>the variables below (x, y, z) were not on the test, they represent real values that I have forgotten</p>

<p>0-25----------26-50--------51-75----------76-100
x--------------y-------------z--------------3</p>

<p>and then they say one person scored 86.</p>

<p>so that would mean the equation is</p>

<p>25x+50y+75z+100(2)+86 which would get you your number right?</p>

<p>I’m curious how alot of people got 1611 as well, did some of us forget to add in an extra 25 or something?</p>

<p>Okay, I remember one question bugged the hell out of me.</p>

<p>It was the one about 9 students on the math team and 10 on the academic team. 11 of them are on one team. How many are on both teams? I mean, logic would say 8 but that wasn’t one of the options.</p>

<p>“and i hope -1 isnt 760 like last month…”</p>

<p>^^^what the eff?</p>

<p>heres how to do it obstinate.</p>

<p>there are 10 people on the academic team
9 people on the math team
11 people on only one team</p>

<p>so what you do is 19-11 and you get 8 right?</p>

<p>But wait!</p>

<p>You need to divide that number by 2 because each individual is counted twice, once for being in the math club and once for being in the academic club</p>

<p>in the end you should get</p>

<p>5 people in the math club only
6 people in the academic club only
4 people in both</p>

<p>now go back and check your work</p>

<p>5+4 = 9 so that satisfies the first statement
6+4 = 10 which satisfies the academic class size
and 5+6 = 11 which satisfies the third condition</p>

<p>hope that helps</p>

<p>OMG I KNEW IT!</p>

<p>My gut instinct was to go with 4 but I just left it blank argh!</p>

<p>For the last sentence completion I put E. For fraternal twins I put C. Because it wasn’t even complex, it was just wrong.</p>

<p>hispter fraternal twins i also put c. i thought the any other and more should be switched.</p>