<p><a href=“http://i475.■■■■■■■■■■■■■■■/albums/rr116/watex/math.png[/url]”>http://i475.■■■■■■■■■■■■■■■/albums/rr116/watex/math.png</a></p>
<p>I find AB has a slope of -1. It’s just apparent The bysection point is (1,1) (Can anyone mathematically prove how?) And the slope of line l must be 1/2.
So I make a function with that info: y - 1 = 1/2(x-1)
I plug in the answer choices to see which satisfies the equation… and NONE do…
Answer is suposedly D</p>
<p>You are on the right track…but if one line has a slope of -1, the perpendicular line has a slope of +1, not +1/2.</p>
<p>But this is easier if you just picture it: the line that perpendicularly bisects the given line is the line y=x. So pick the point with equal x and y coordinates…</p>
<p>The slope of the line is 1. So yes, it’s D.</p>
<p>“Can anyone mathematically prove how?” –> Midpoint of (0,2) and (2,0) is (1,1), the point that the line is bisected.</p>
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<p>I’ll give it a shot? The midpoint of any segment will be ([x1+x2]/2, [y1+y2]/2). Basically, you’re just finding the averages of the x and y points. The midpoint of a segment will be the point at which the bisector goes through; I’m pretty sure that’s just a definition thing. So, the point that the bisector goes through is the midpoint, therefore the midpoint is found by the above formula to be (1,1). So yeah, the bisection point is generally pretty apparent, as it should be; averages are pretty apparent, especially in this case.</p>
<p>Basically, it has to be D because if the slope of the line shown is -1, then the perpendicular line is 1/1 or 1. (3,3) would be the only point on a line that would work.</p>
<p>thanks guys. im seriously bewildered at how i made such a mistake</p>