Math for March SAT 2009

<p>I think i wrote 90 for that one but I’m always wrong</p>

<p>You don’t need to find out the combo of a and b in f(16). You only have to use the function they give you. This is no different from a function problem where they use symbols. Since any values for f(ab) = f(a) + f(b), f(4*4) = f(4) + f(4). Plug in the value they give you to get 12 + 12 = 24.</p>

<p>Okay about the rope one…I just realized my critical error…I divided 60 by 4 instead of 5…awww shucks D:</p>

<p>Quick question guys that I need answered:</p>

<p>You know that math and science class question? How far into the section was it? Was it one of the last questions, in the middle, or early.</p>

<p>The reason I ask is because at first I remember I was going to skip it and come back to it later. I ran out of time on that section so I didn’t have the time to go back and do it. The problem is that, for some reason, I remember not leaving any blank on that section. But I also remember skipping that problem. So that means that I MIGHT have skipped it, but filled in the bubble for the next answer in that answer, meaning that all my answers from that point on would be wrong.</p>

<p>I’m hoping this isn’t the case. I can’t really remember if I left any blank or not. I’m hoping that at worst, all I did was fill it in with a guess.</p>

<p>Answers I remember</p>

<p>4root3
36 degrees
5000
10%
90 (I put 104 >_<)
21
24
0<a<7
40/3
.833 or 5/12
5
4
144
50
2725</p>

<p>I believe the math/science question was around the middle, but my memories are vague.</p>

<p>there was one about finding median temperatures (with a graph)</p>

<p>was the answer 88?</p>

<p>which answer was 2725 for?</p>

<p>the thing is you have no clue that f(1) is equal to a value so all you know is four stick with the given and youll be fine.</p>

<p>yeah i think it was 90, i cant remember the number of students in each class.
U solve the prob by subtracting 14 from both classes, add both classes and then add the other 14 students.</p>

<p>that system is waste of time for rectangle because if you just use the super pythagrian therom and the 3,4,5 triangle it makes the problem ten times shorter.</p>

<p>how did you guys do the polygon one? n(n-3)/ something</p>

<p>somebody here said 160/9 but that is an impossible answer since there arent enough bubbles. i not apposed to another answer just one that fits.</p>

<p>Do any of you guys remember the question that had a circle that was half shaded in and a line AB running down the middle of it? Was the experimental or the real thing? I think I got that one wrong…</p>

<p>it was not experimental, it was 4root2 i believe</p>

<p>

</p>

<p>True, I guess the function could only be defined at certain values. Darn loopholes…</p>

<p>I believe I put 4root2 as well.</p>

<p>yeah i got 4 root 2 for one answer and 4 root 3 for another</p>

<p>I’m still hanging in there with a -2… I will die if I get -3 after getting an 800 Math II x.x</p>

<p>Same thing 112358. Math always = 800. Today -2…</p>