Math for March SAT 2009

<p>Luckily i finished that section with the absolute value question with enough time to go through all the choices and plug in values…no idea how to do that one. There was a diagram one that threw me off, but other than that the math was pretty easy</p>

<p>I think I put something between 45 and 50 for the p and x question. It may have been 50, but it simply didn’t mathematically make sense to me. The actual graph wasn’t worth a damn either, because I remember 50% working but looking at the graph x% definitely wasn’t 50.</p>

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<p>That’s how I did it. Unfortunately I don’t remember what I ended up going with.</p>

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Yeah it was the last problem on that section (section 2 on my test). Are you sure you got it right? The answer was abs(x-a-5) < 5</p>

<p>P/x question could be 43, 46, 49 if they wanted whole numbers, but i think the possbility’s endless with decimals?</p>

<p>I think the answer choice was C or something</p>

<p>Didn’t the pie chart say that it wasn’t to scale? Anyways, going back over the x and p along with the absolute value took up all of my time, so I couldn’t check my other answers. Hopefully there were no stupid reading or algebraic errors.</p>

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<p>Something else on that same page said it I’m pretty sure, or maybe my eyes were playing tricks on me. </p>

<p>TI-89’s solver is quite handy on the test btw.</p>

<p>It DID say that the pie chart was not drawn to scale. I’m sure about that.</p>

<p>Anyway, B or C for the absolute value number line?</p>

<p>It was drawn close enough, the answer had to be in that range because 2p < x < 3p</p>

<p>I think it was B (can’t remember what choice was what, but I think the right one was B). I didn’t plug in values, it just seemed obvious to me… if you take a from x and subtract 5, it has to be less than 5. If it’s more than 5, then x was more than 10… </p>

<p>Seems pretty simple… </p>

<p>The function one, on the other hand… Just wow…</p>

<p>What was the function one?</p>

<p>f(ab)?</p>

<p>answer?</p>

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<p>And 50% did indeed fall into that range, no? </p>

<p>It’s just that there was no way x% was drawn to even a decent scale considering the several possible answers, which kinda defeats the purpose IMO. But I’m not the College board.</p>

<p>What was the function one?</p>

<p>f(ab)?</p>

<p>answer? </p>

<p>Answer was 24. </p>

<p>f(ab) = f(a) + f(b)
f(4) = 12
f(16) = ?
f(4*4) = f(4) + f(4) = 12 + 12 = 24</p>

<p>Area of semicircle = 4pi
–> A of circle = 2(4pi) = 8pi
A = pi(r^2)
pi(r^2) = 8pi
r = sq rt of 8 = sq rt of (4 x 2) = 2 radical 2
AB is the diameter so multiply the radius by 2 —> 2 x (2 radical 2) = 4 radical 2</p>

<p>Wow… I forgot to multiply by 2 ^ =@</p>

<p>I didn’t say it was…?</p>

<p>haha, sorry if it was confusing. my definition of range is very fluid. i just meant around 40-50</p>

<p>Okay good, got that one.</p>

<p>Thankfully there weren’t any confusing word problems this time around</p>

<p>For the circle that was centered at point (-3,0), the correct answer was (-1,1), correct?</p>

<p>I can’t remember if I accidentally put 8 radical 2 instead… I am driving myself crazy trying to remember what I put!!!</p>

<p>Yeah, the others were obviously out of the circle.</p>

<p>K thank you. Have we gotten definite confirmation on 40/3 for the triangle one?</p>