<p>Today, I took the diagnostic test in the Barron’s Math II book and received a 760. I went over all my mistakes and dont understand one question, 42. It states: If A=arctan(-3/4) and A+B=315, then B=… </p>
<p>When I did the arctan on my calculator, it yielded a value of -36.87, so I added 180 to it because it would have the same tangent, getting 143.13. Then I subtracted that from 315 and got 171.87, one of the answers. The answer key says that the answer is 351.87 because when you do 315-tan(-3/4), you get that when the arctan is -36.87. I dont understand this question because arent there an infinite amount of values that satisfy arctan(-3/4). Both my approach and theirs were correct since that expression is applicable to so many angles.</p>
<p>but arent there an infinite number of angles that satisfy arctan(-3/4) that’s why I added 180 just out of convenience to make it positive… I dont see why it should change the answer A is still arctan(-3/4) even if I add 180 thats what I dont understand</p>
<p>The inverse tangent function on the calculator has a range restricted to
-90º<y<90º, the principle values. Thus A can be only -36.87º.</p>
<p>edit:
i looked up the problem and the “t” in tan^-1 is not uppercase indicating that the range is restricted to the principle values, so i’m assuming this is an oversight on the testmaker’s part.</p>