<p>Which of the following represents the area of the five-sided figure above?</p>
<p>A) 1/2 X^2 + 3/2 Y
B) 1/2 X^2 + 3Y
C) 3Y - 1/2 (X-3)
D) 3Y + 1/2 (X-3)
E) 3Y + 1/2 (X-3)^2</p>
<p>The numbers on the figure are: “X” on the far left side of the figure, “3” on the far right side of the figure, “Y” is the length of the bottom side of the figure. The side drawn that cuts the rectangle is my drawing, not part of the problem, therefore the figure all in all is five sides if you count them. And finally, the measure of the angle at the top left is 45 degrees.</p>
<p>Sorry for the ****ty picture. And thanks for number 2!</p>
<p>the image’s answer is D, 3y + .5(x-3)^2, and not A. This is becasue you can find the length of the entire bottom strip with y<em>3. the remaining vertical figures for the triangle to the left would be x-3 (because you cannot account for an area twice, and because it is a right triangle, you know that the horozontal figure will be x-3 as well. the area of a triangle is .5l</em>w, so you add teh values together to get 3y + .5(x-3)^2</p>
<p>I think you misinterpreted the length of the bottom side. It is not x and y. It is only y.</p>
<p>Side note to everyone: The X written on the bottom side of the figure is not part of the problem, nor is the short line that cuts the rectangle in half either.</p>
<p>sorry, i meant E. i said taht it would be 3y + .5(x-3)^2 i just put the wrong letter. my steps are still applicable just erad it instead of skipping to my final answer</p>