Math question

Test Preparation SAT Preparation
1

<p>How can you do this problem without graphing?</p>

<p>How many numbers between 35 and 300 can be expressed as 5x + 1, where x is an integer?</p>

2

<p>is the answer 53???</p>

3

<p>Yes it is :)</p>

<p>Also, I have another problem that I need help on:</p>

<p><a href=“http://i55.■■■■■■■.com/eijswg.png[/url]”>http://i55.■■■■■■■.com/eijswg.png&lt;/a&gt;&lt;/p&gt;

4

<p>(20)(pie)???</p>

5

<p>I do not have the answer to the second one, unfortunately. How is it done?</p>

6

<p>okay so dude, the explanations for both questions… okay as for the second one… you somehow have to notice that when two circles overlap that one of them is tangent to the center of the other then it is basically occupying half of its area so since that happens four quarters to make a whole new circle “one fourth multiplied by 4” then you can just easily use the radius of one of the circles, 10 in this case, to just substitute it in the equation of the Circumference/Perimeter
Circumference= 2(pi)(r) = 2(10)(pi) = 20pi</p>

7

<p>for the first one… you get the difference so 300-35=265 then you divide it by 5 to make sure to get all the numbers that are divisible by 5 to satisfy your equation.</p>

8

<p>What about subtracting the 1 though for the first problem?
Wouldn’t it be:
5x + 1 = 265
5x = 264
x = 52.8</p>

9

<p>Can someone else explain the circle question? I still don’t understand!</p>

10

<p>Like "that when two circles overlap that one of them is tangent to the center of the other then it is basically occupying half of its area " ??</p>

11

<p>I got a question! whats the fastest way to sovle this? if xy=2 and yz=5 and xz = 10 then whats xyz</p>

12

<p>^ try multiplying them all together: you’ll get (x^2)(y^2)(z^2) = 100. Take the square root of both sides and you are home free.</p>

<p>As for the circle one…Each of those arcs is 1/6 of the circumference. Draw the triangle that connects the centers and also the triangles from the centers to the points of intersection. ALL of the sides are radii so all of the triangles are equilateral and so all of the intercepted arcs are 60 degrees or 1/6 of the circle. Then, the perimeter of the desired shape consists of 6 of them. So its perimeter is the same as the circumference of one of the circles with radius 10.</p>

13

<p>oo wow thanks!</p>

14

<p>

The way I did this problem was find the smallest and largest x value to satisfy the 35-300 limit. The smallest x=7 (5*7 + 1 = 36) and the largest x=59 (I started with x=60 but then realized it was 301 so it was x=59). The difference +1 is all the numbers that satisfy the problem: 59-7+1 = 53</p>

15

<p>yah I did it like blob793 did!!!</p>