<p><a href=“ImageShack - Best place for all of your image hosting and image sharing needs”>ImageShack - Best place for all of your image hosting and image sharing needs;
<p>What do you think ?I thought the answer was A .THere are 3 possible combination satisfying Meredith
w w w
r r r
b b b</p>
<p>thinkin its E. use combination formula</p>
<p>Is it B? LOL I just counted since there’s not that many…</p>
<p>Well… It’s not 3.
She could wear a red hat with: blue sweater/white jeans or white jeans/blue sweater.
She could wear a blue hat with red sweater/white jeans or white sweater/red jeans.
She could wear a white hat with red sweater/blue jeans or blue sweater/red jeans.</p>
<p>So I think the answer is 6 unless I am missing something…?</p>
<p>You can’t use the combination formula because you can only wear once of each piece of clothing at one time.</p>
<p>3C1 * 3C1 * 3C1 = 27</p>
<p>I think it means how many different combinations of 1 red, 1 white, and 1 blue she can wear.</p>
<p>It can’t possibly be 27, though… you can’t use two hats, etc. You need one of each clothing being each a different color.</p>
<p>Do you have the answer, or no?</p>
<p>Definitely not 27, as Zupchurch said. Best way to do it is just count it…it really isn’t that complicated cuz there’s only 6 ways of wearing red, white and blue AND 3 different pieces of clothing</p>
<p>It’s B. I’m surprised this question gave you guys so much trouble. If it was just asking for how many combination, then it would be 27.</p>
<p>This is a “counting principle” example. There are more of these on the SAT by far than anything involving fancy combinations and permutations. </p>
<p>Just ask yourself: how many choices does she have for her first garment? 3 (no matter what she puts on first, she can choose any of the three colors.)</p>
<p>Now, how many choices for her next garment? 2 – she can’t choose the same color she already picked.</p>
<p>Then, how many choices for the last garment? 1 – she must pick the color she hasn’t picked yet.</p>
<p>3 x 2 x 1 = 6.</p>
<p>6 is the answer</p>
<p>you have 3 available colors for the hat (r;w;b) , 2 remaining for the sweater and 1 which is the only one left color thus it’s
3x2x1 = 6. The misleading point was that it could be inferred that all the clothes she wears should be of one color (r;r;r), but it’s said “red,blue and white outfit” so it’s not right.</p>
<p>^yea its 6.</p>
<p>Yeah my bad. I misread it. It should be 3C1 * 2C1 * 1C1 = 6.</p>
<p>how can it be 6? It’s 9</p>
<p>it is 6</p>
<p>Red hat blue pants white sweater
Red hat white pants blue sweater</p>
<p>Blue hat, red pants white sweater
Blue hat white pants red sweater</p>
<p>Whit4 hat red pants blue sweater
White hat blue pants red sweater</p>
<p>its not 9,
this
“It should be 3C1 * 2C1 * 1C1 = 6.” is correct</p>
