  # Math Question

<p>Gift certificates were sold in the month of July. Each gift certificate was worth either \$2, \$3, or \$5. Twice as many \$2 gift certificates were sold as \$3 gift certificates, and twice as many \$3 gift certificates were sold as \$5 gift certificates. The total value of all the gift certificates was \$57. How many \$3 gift certificates were sold in July?</p>

<p>I got 6.</p>

<p>I set the value of the gift certificate times the number of gift certificates.
So the total value of the \$5 ones equals \$5*(# of certificates) --> 5x</p>

<p>I then set the same for \$3 and \$2, but multiplied the amounts. </p>

<p>There are twice as many \$3s as \$5, so the next part would be 2(3x).
Then since there are twice as many \$2s as \$3s, for four times as many \$2s as \$5s, I would set it to 2[2(2x)] or 4(2x)</p>

<p>After that, add the three parts together and set equal to the total value:</p>

<p>5x+2(3x)+4(2)=57</p>

<p>5x+6x+8x=57</p>

<p>19x=57</p>

<p>Solve for x and you get 3 \$5 gift cards.</p>

<p>But since there are twice as many \$3 gift cards as \$5 gift card, solve accordingly:</p>

<p>2(3)=6</p>

<p>Thanks so much!</p>