Math Question

<p>Gift certificates were sold in the month of July. Each gift certificate was worth either $2, $3, or $5. Twice as many $2 gift certificates were sold as $3 gift certificates, and twice as many $3 gift certificates were sold as $5 gift certificates. The total value of all the gift certificates was $57. How many $3 gift certificates were sold in July?</p>

<p>I got 6.</p>

<p>I set the value of the gift certificate times the number of gift certificates.
So the total value of the $5 ones equals $5*(# of certificates) --> 5x</p>

<p>I then set the same for $3 and $2, but multiplied the amounts. </p>

<p>There are twice as many $3s as $5, so the next part would be 2(3x).
Then since there are twice as many $2s as $3s, for four times as many $2s as $5s, I would set it to 2[2(2x)] or 4(2x)</p>

<p>After that, add the three parts together and set equal to the total value:</p>

<p>5x+2(3x)+4(2)=57</p>

<p>5x+6x+8x=57</p>

<p>19x=57</p>

<p>Solve for x and you get 3 $5 gift cards.</p>

<p>But since there are twice as many $3 gift cards as $5 gift card, solve accordingly:</p>

<p>2(3)=6</p>

<p>Thanks so much!</p>