<p>Amanda travel to work from home in 60 minutes. If,on her way home,she
increases her average speed by 20 % and she travel by the exact same route,
how many minutes will it take her to get home ?</p>
<p>1)48
2)50
3)54
4)60
5)64</p>
<p>*okay. Put “P/60” as your per-minute speed. Take “P” as the symbol for the total distance between work and home. Now, the new speed should be increased by 20%, so times “P/60” by “1.2.” You get 0.02P.
Since this is your new speed and you want to get the time it takes, you should divide the distance P by the new speed 0.02P. You’ll get 50 minutes after reversing 0.02. The answer is 2.</p>
<p>A jar contains five marbles,five of which are white
and the rest black. What is the least number of white marbles
that must be added to the jary so that least three-fifths of the marbles
will be white?</p>
<p>*I don’t understand. Five marbles in total??</p>
<p>If x and y are positve integers such that x^2 + y^2 = 41,then what is the value of (x + y)^2?
I knew by brute-forcing that 4^2 + 5^2 = 41,but is there mathmatical way to tackle this problem!?</p>
<p>*For this type of problem, you can’t get a logical method. x+y squared x^2+2xy+y^2, and there is no way you can get the value of 2xy from the provided info. Just do your best in guessing !</p>
<p>In one basketball game, Tamara made 50 % of her shots,and in the two games,she made 60% of her shots.
In the two games,she made 52 % of her shots altogether. If she took a shots in the first game and b shots in the second game, what is the value of a/b?</p>
<p>*The shots you made in the first game is represented as .5a, because you have to times the percentage by “a” (the total no. of shots). Do the same for the second game and you’ll get .6b.
(.5a+.6b) should be put over (a+b), which is the total no. of shots for both games. This fraction, (.5a+.6b)/(a+b), should equal 52%, or .52. Cross-multiply.
You’ll get an equation like this: 2a=8b, in other words, a=4b.</p>
<p>Replace a with 4b in the a/b formula. You’ll get 4. The answer is 4.</p>
<p>I hope this helped you! :)</p>