<p>Yeah, viggy’s solution in post #599 to the median question is probably simplest. I believe the numbers were as follows, with the y-axis numbers (number of cars) in the top row and the x-axis numbers (gas mileage) in the bottom row.</p>
<p>40 50 40 30 10
25 26 27 28 29</p>
<p>There were therefore 170 total cars. That means there are 85 cars less than (to the left of) the median gas mileage and 85 cars greater than (to the right of) the median gas mileage. If you listed all of the cars in numeric order, you’d have forty 25’s, then fifty 26’s, then forty 27’s and so on. Both the 85th and 86th cars (between which the median lies) will fall within those cars with gas mileage of 26 (the last car with 26 mileage will be the 90th car…the 91st car would be where the 27’s begin).</p>
<p>if you looked closely at the graph, there was a point on the y-intercept. my estimation was 7 at first, but then i noticed that they had plotted the point 0,13ish</p>
<p>what was the answer to the question with a circle(but without the outer lining, so it was just the angles) cut up to like 6-7 angles…there were like 3-4 X’s and Y’s…
some of the choices were x+y=120 or x=y…what was it? i put x=y but i don’t know for sure…</p>