May 2010 Math SAT Thread

Test Preparation SAT Preparation
721

<p>I think it was 6 as well. One function increased by 2.5 and the other increased by 1.5. I can’t remember the starting values, but when I set them equal to each other I got 6.</p>

<p>One question asked how many two-digit numbers have both digits add to 4 and multiply to 4. I believe this was just one? (22).</p>

<p>Oh, and for the problem with the rectangle ABCD in circle A and vertex C lying on the circle: was the answer 8? </p>

<p>It was given that the radius was 8 and side AB of the rectangle was sqrt(3). However, diagonal AC would be 8 because it’s also a radius and then BD = AC because the diagonals are congruent which means BD = 8.</p>

<p>This problem seemed a bit too easy considering it was #18 or 19, so I’m skeptical that I got it correct.</p>

<p>Also, a #20 had a function in the form f(x) = 2x^2 + ax + b and asks for a + b. The points (0,2) and (0,-3) are given. Multiplying (x-2)(x+3) gives x^2 + x - 6. Multiplying by 2 given 2x^2 + 2x - 12. 2 + -12 = -10.</p>

722

<p>I don’t remember the questions that have the following correct answers: 12, 15, 16, 50.</p>

723

<p>Around what score would you estimate 3 wrong would be? Totally missed one, two careless mistakes.</p>

724

<p>Does anyone remember the exact question and how the solved it for the number of rectangle boxes can fit in something? Thanks. As this is the only one i unsure about because i forgot witch one i put.</p>

725

<p>Yeah, any insight on curve compared to released ones?</p>

726

<p>@Cuthalion 720 maybe</p>

727

<p>“Does anyone remember the exact question and how the solved it for the number of rectangle boxes can fit in something? Thanks. As this is the only one i unsure about because i forgot witch one i put.”</p>

<p>It was something along the lines of: “how many 20 cm x 5 cm x 10 cm boxes can fit in a 1 meter cube?”
20 cm x 5 cm x 10 cm = 1000 cm^3 = 10^3 cm^3.
A 1 meter cube = (100 cm)^3.
Simply divide: 100^3 cm^3/10^3 cm^3 = 10^6/10^3 = 10^3 = 1000 cm^3.</p>

728

<p>anyone think that a 50/54 raw score could be a 720?</p>

729

<p>Do you guys remember getting the answer 50? I don’t.</p>

730

<p>Ok. Just to clarify, the question pertaining to the pie graph was ridiculously easy, right? It gave you 2 percentages, so 100 - the 2 percentages = 4-6 percent or something? Then find 4-6 percent of whatever number was given = 72?</p>

731

<p>And for the first MC question on the list, was the question given as 6 = 4x? It’s the early ones i forget.</p>

732

<p>^i think it said “four times a number is equal to six. what is the number?” or something like that. but i could just be making that up…</p>

733

<p>DoctorTye</p>

<p>I remember it being like 6% (anyone else remember it being 6% of some given number)</p>

734

<p>i think it was 2/3?</p>

735

<p>^yes, 1200 people were interviewed. and 6% of them said they packed that day.</p>

736

<p>could the answer 50 be to the question where it asked:
'if the arithmetic mean of 3 numbers is 50, and x<y<z, and y =30, what is the smallest possible value of x?" or did it ask for z? but i dont think i put 50… im not even sure anymore; does anyone remember that question/the answer?</p>

737

<p>Seems like they always pick a percent between 1-9 so that when people type it in on the calc they accidently do .6 instead of .06. I hate these people lol.</p>

738

<p>Candycanes the answer was 91 it asked for Z.</p>

739

<p>oh i’m 90% sure i put 91 for that one, thanks :)</p>

740

<p>x < y < z. x + y + z = 150. y = 30
In order for z to be at its smallest value, the value of x has to be at its largest. Since y has a value of 30, x must have a maximum value of 29. 150 - 30 - 29 = 91.</p>