<p>I recently saw a post that pointed out an error in one of the questions at mcatquestionaday.com.
I think there is another mistake for yesterday’s question.</p>
<p>You are given three capacitors of capacitance X. If you are allowed to place the capacitors in a circuit in any fashion, how many different effective capacitances can you get? </p>
<p>(a) 1
(b) 2
(c) 3
(d) 4</p>
<p>Given answer and explanation:
c) You can have all three capacitors in parallel, all in series, or two in parallel in series with another capacitor. This gives only three possible capacitances. </p>
<p>But the possibilities are </p>
<li>All in series.</li>
<li>All in parallel.</li>
<li>Two in series in parallel with another capacitor.</li>
<li>Two in parallel in series with another capacitor.</li>
</ol>
<p>So the answer seems to be 4 but it’s 3. ???</p>