MOD for Chemistry 3A?

<p>Does anybody know if the MOD is cumulative for the final exam, or is it just those 6 on the pdf?</p>

<p>Thanks.</p>

<p>Not cumulative. And fyi just in case, we’re only being tested on those six except it’s a different format from the last exam…instead of matching the molecules to the descriptions, each MOD will appear as a starting material. .___.</p>

<p>Thanks. He said in lecture that the MOD would be worth more too right?</p>

<p>Decimal: Can you clarify? So its still matching, but its the synthesis reagent of the MOD?</p>

<p>From my understanding, there will not be matching this time because Pedersen said in lecture that all that did was raise the average by 10 points. So he wanted to try something different which was to have all the MODs show up somewhere on the exam.</p>

<p>So at least from SLC’s mock exam, it seems that the MOD could appear as the starting materials for predicting the products, etc.</p>

<p>Basically, he said that we could look at each of the six and try putting it through every possible reaction.</p>

<p>I don’t know anything about the MODs being worth more since it’s just like any other exam except we’ve kinda been given a peek preview, so to speak, at the starting materials?</p>

<p>^^Thanks, that clears it up.</p>

<p>That was sort of my understanding as well, but I was a bit confused as to how the MOD would be worth more since thats what I heard from other students.</p>

<p>I’m curious, what’s MOD?</p>

<p>Molecule of the Day, something Professor Pedersen does at the end of each lecture (during which I breathe a sigh of relief).</p>

<p>So he gives us the name and structure of an interesting molecule and tells us why it’s interesting. I liked the previous batch we had more…there was this one molecule that’s released when bees detect the presence of a hornet and so that alerts the other bees to gather around the hornet in a sphere of heat which crushes the intruder.</p>

<p>That must be a really sloppy description but hey, I just came back from the final for this class.</p>