<p>when you put quarterly, 5.3%, 3500 principle, and 1 year into a online savings calculator, you get 3689.22.</p>
<p>Man, from reading this forum it sounds like a good bunch of us got blindsided by a ton of traps.</p>
<p>I hate traps.</p>
<p>Wow, looks like the compound interest question was worded differently after all. Interestingly enough, that still leaves me at 7 omitted and 1 incorrect, because one answer that I thought was originally incorrect turned out to be right (after checking the previous posts on this thread). So I’m predicting that I got a 780 (or a 790 if I got lucky on that other question as well… can’t remember it now for some reason).</p>
<p>From the list on page 21:</p>
<p>Number 21, I have a problem with-</p>
<p>I agree with the first, 1/x=1/y, but the third answer choice ends up being</p>
<p>y=1/(x-1)+1 x=y/(y-1) </p>
<p>(verified by my ti-89 and Wolfram: <a href=“inverse of y=1/(x-1)+1 - Wolfram|Alpha”>inverse of y=1/(x-1)+1 - Wolfram|Alpha; )</p>
<p>the inverse is missing a plus one.</p>
<p>There was also the question about 7^6=10x+y, solve for y: I got y=9
sine 7^6=(117649-9)/10=a whole number.</p>
<p>sine(1/2x+a)+k</p>
<p>sorry i cant remember the value of a and k in the equation…</p>
<p>f(x) = 1/(x-1) + 1
f(x)inverse => x = 1/(y-1)+1
=> x-1 = 1/(y-1)
=> y-1 = 1/(x-1)
=> y = 1/(x-1)+1</p>
<p>looks like I and III for that problem. I think you may be over thinking it, Ribo.</p>
<p>Ah, I see what Wolfram did.
from step 1 of the inverse:
=> 1/(y-1) + 1
find LCD (y-1) => y/(y-1)</p>
<p>it’s the same value, just simplified by combining the two terms. It’s still the inverse, though.</p>
<p>bleh. Yes…I have a bad habit of running through these questions using the CAS on the 89, which puts problems in different formats all the time.</p>
<p>@teddybear52 : i think it was |cos(1/2 x)| or sth . I got 2 pi for that question</p>
<p>
</p>
<p>I might be wrong, but from what I remember, the question didn’t specify that the given interest was annual. All it said was 5.2% interest is compounded quarterly. Please could someone say what the correct answer is and how they got it?</p>
<p>I’m 100% sure about what I read:</p>
<p>The man put $3500 in a bank with 5.2% ANNUAL interest compounded quarterly. How much would he have after a year?</p>
<p>
what question was this?</p>
<p>and fledgling why would you omit 7 if 6 is the max for 800</p>
<p>also, if -8 is 780 or 790, how much does it decrease thereafter for each decrement in the raw score?</p>
<p>For the absolute value trig function, you can’t use that period formula because it also turns the negative parts are become positive. Since the absolute value of the negative part is the same as the curve above. You should repeat twice. U must then divide the period by 2. 4pm/2=2pi. U can easily prove this by graphing it.</p>
<p>I guessed on about 4 and skipped like 8. I’ll probably end up with like a 580.</p>
<p>D:</p>
<p>Does anyone still remember any more questions from the test? We should start an answers list, or add onto the one posted earlier in this thread.</p>
<p>@emad, yes that’s what i saw too</p>
<p>@terywj, no, it definitely won’t be that low. you’ll definitely get into 600, at LEAST. probably high 600 or low 700</p>
<p>Ok guys. I know making consolidated list now is kinda crazy. But I really did. I read all those 27 pages and though for some I cant recall I did my best. Those who want to fix later please quote all of the list and bold what you gonna fix.<br>
Some one has already posted a list on page 21 but this list I made on what you guys discussed already so maybe it’s a bit different. Good day!</p>
<p>CONSOLIDATED LIST
- Question asking about ax^3 … -> a>0
- Inverse equations: I and III (I is y = 1/x and III is y = 1/(x+1) +1)
- Roots in the between x=-2 and x=-1
- Mo/2^t
- Probability of call: 4/9 (?)
- New square = 4 times original square
- last problem: abs(sec(x))
- Standard Deviation: (Still) 0.1
- Period of abs(cos(x/2)) is 4pi (many also said 2pi)
My opinion: 4pi for sure, just graph y = cos(x/2) and y = cos(x) together you’ll see - Probability: 7280 (cant recall the question)
- Slope of a line: 130 degree
- Magnitude of vector a-b (or b-a not sure) is 11
- something with abs(x)/x and answer is 2 (cant recall, can some one help?)
- 1 foot = 12 inches -> answer: 10.2 (10)
- Function with Exactly 2 real solutions: (x^2-1)(x^2+1)
- height of the cone: 24.84
- (3x^2-3)/(x-1) is undefined at x=1
- ax^2 + bx + c has maximum 2 solutions
- 2 parallel lines: slope k=m</p>
<p>Come on guys! We need help. Still many questions to go XD</p>
<p>^unsure about 5, (OMG I MESSED UP ON 8 noooooooOOOO D:), 9, 15, 18</p>
<p>can someone recall no 10 and 13 for me?? :(</p>
<p>Some answers I didn’t see include: the one where I think g(x) was 2x - 2, and the one where the slope was -1, after you did the slope formula and got 1/2 - 0 / -1/2 - 0</p>
<p>
</p>
<p>I simply forgot how to answer them lol. And I’m not so sure about 6 being the maximum for an 800… I’ve seen 43/50 ending up being an 800 multiple times on this forum (read through quite a few Math II threads).</p>