<p>^I’m hoping that’s the curve for this test, it seems like it will be. Not that I’m even close to 800, but it would maybe save me from hitting the 600s.</p>
<p>The call was 2/9 i think. You added the probabilities, because they were independent events.</p>
<h1>18, why is only 2 solutions? I thought it was infinite. It said ANY real numbers didn’t it?</h1>
<p>^
I put infinite as well.</p>
<p>Again please quote and bold. Quote and bold.</p>
<p>neekzg, thanks for your help. The 2x-2 think I have on my list but I forgor to type. Im pretty sure about that one either. The slope one should be number 11, I messed up (and fixed). Can you remember which one with the answer of 130 degrees??</p>
<p>CONSOLIDATED LIST
- Question asking about ax^3 … -> a>0
- Inverse equations: I and III (I is y = 1/x and III is y = 1/(x+1) +1)
- Roots in the between x=-2 and x=-1
- Mo/2^t
- Probability of call: 4/9 (?)
- New square = 4 times original square
- last problem: abs(sec(x))
- Standard Deviation: (Still) 0.1
- Period of abs(cos(x/2)) is 4pi (many also said 2pi)
My opinion: 4pi for sure, just graph y = cos(x/2) and y = cos(x) together you’ll see - Probability: 7280 (cant recall the question)
- Slope of a line: -1
- Magnitude of vector a-b (or b-a not sure) is 11
- something with abs(x)/x and answer is 2 (cant recall, can some one help?)
- 1 foot = 12 inches -> answer: 10.2 (10)
- Function with Exactly 2 real solutions: (x^2-1)(x^2+1)
- height of the cone: 24.84
- (3x^2-3)/(x-1) is undefined at x=1
- ax^2 + bx + c has maximum 2 solutions
- 2 parallel lines: slope k=m
- The question with compound funtion: 2x-2</p>
<p>2 solutions because the degree of the equation is 2, so the max number of solution is 2. More simply, y = ax^2 + bx + c is a function of parabola which can cut Ox at only 2 points or less. Answer should be 2 if I recall the question correctly</p>
<p>Also, how do you do the probability Q? It said there are 20 testers, they take 4 and do a test. Then they take 1 person and do a special test. How many options are there? I thought it was 20x19x18x17. But that was definitely not right :p</p>
<p>^
You do: </p>
<p>[ 20! / ((20-4)!4!) ] * 4! I believe. Can anyone confirm this?</p>
<p>if you were doing a permutation, you would have the bottom of the fraction is 4! and 16!, not four twice.</p>
<p>i can remember that one: 20C4 multiply 4C1 = 19380 (??). no one wants to continue the list. So fine :(</p>
<p>@ Jasonvdm
Sorry! Typo, haha.</p>
<p>There was the question where k was a constant, and C was concentration in mols I think, with concentrations of 1 = .2C^something and 16= .8C^something . My answer was 2 to that question, I’m not positive that it’s right though.</p>
<p>No problem :D. You may be right with your equation (the fixed one!) but idk, I thought since only 4 people were picked, you did 20x19x18x17. I got lost after that.</p>
<p>Regarding the ax2+bx+c = x problem, tell me what you guys think about this!
<a href=“x=ax^2 + bx + c solutions - Wolfram|Alpha”>x=ax^2 + bx + c solutions - Wolfram|Alpha;
<p>from my perspective, it seems that there would be only ONE root since there’s no ± sign… I didn’t put 1 myself, but this topic made me wonder so I searched it up…
I put infinite, though, forgot my reasoning…</p>
<p>@neekzg
I got 2, as well.</p>
<p>@Jasonvdm
It’s actually a combination equation, since there’s no specific order in the choices. 20<em>19</em>18*17 would represent the number of ways 1st-4th place medals (order here matters) could be handed out among twenty people.</p>
<p>Jason- 20C4x4C1. I think that’s the way I did it. And I got 2 roots for the ax^2+bx+c though I thought the question was awfully ambiguous.</p>
<p>The question was first choose 4 ppl among 20 and choose 1 among 4 right? so 20C4x4C1 :-s</p>
<p>lol great minds think alike hesterprynne? :)</p>
<p>But my argument is. You choose one person, then you only have 19 more to choose from, and so on. There IS an order of choices.</p>
<p>The absolute value one is definitely 2pi. Think of it this way when you get Isin(x)I and Icos(x)I u get a period of pi. U should try graphing the absolute function.</p>
<p>Courtney explained it to me, i’m an idiot. haha</p>