<p>@Corvids uh no which year of the formula sheet are you using?</p>
<p><a href=“Supporting Students from Day One to Exam Day – AP Central | College Board”>Supporting Students from Day One to Exam Day – AP Central | College Board;
<p>Beer’s Law - Question 5.
I got through it without even knowing what it was though.</p>
<p>A lone pair with 4 bonds is called Seesaw.
What’s two lone pairs with 4 bonds called? Trigonal bypyramidal?
Do we need to remember the bond angles?</p>
<p>Yea it gave some data, asked for calibration plot and then asked to use that plot for finding concentration.
2006 F.B Q.5.</p>
<p>Edit: Abrayo beat me to it</p>
<p>And it’s square planar I think. I am not memorizing all the angles though.</p>
<p>I would also memorize solubility rules! I’m taking the test tomorrow!</p>
<p><a href=“Supporting Students from Day One to Exam Day – AP Central | College Board”>Supporting Students from Day One to Exam Day – AP Central | College Board;
2009 FRQ. Fast forward to 6c.
How does that make sense? Doesn’t that completely throw out VSEPR theory?
I don’t recall anything about predicting molecular geometry based on… that.</p>
<p>@scholarship: it was on last year’s formula sheet at least. It’s on the last page under osmotic pressure. A = abc.</p>
<p>yo i need some quick help ~
i was taking one of the released exam mcqs and i got this one question wrong but i guess i got it wrong cause i didn’t know it.</p>
<p>it basically asked to match up the pairs and so the question was find the oxidation-reduction reaction. answer was:
2 K(s) + Br2 (l) -> 2KBr (s)</p>
<p>how the f is that a oxidation-reduction reaction? isn’t an oxidation-reduction reaction one where u lose electrons and gain. i dont get it at all.</p>
<p>@abrayo for ur second question, it would not a trigonal bypyramidal. trigonal bypyrmidal is a basically X(tiny)5.[right?] </p>
<p>also guys can i get a quick run down for bond order?</p>
<p>2006:
It says a saturated solution has so and so molar concentrations of ___ and ___. Then it says, if the volume was doubled, what would happen to their concentrations?</p>
<p>It says it’s the same because it’s a saturated solution . . . ohhkay.
What if it was unsaturated? Would it become half?</p>
<p>Bond order - singles are 1, doubles are 2, triples are 3?
I hope so.</p>
<p>Also, once you finish Part A, I know you have to wait for time to finish before you can go to Part B. But once you’re allowed to, are you able to return to Part A, even if you don’t have a calculator? I know you can do this with Calculus so I’m just wondering if you can with Chem as well.</p>
<p>ALSO do you need concluding statements for your answers?</p>
<p>no calc once ur done with part b and u wish to go back to part a. </p>
<p>guys i have another question(i am losing my mind. i believe u have to do ICE right?):</p>
<p>THe value of the acid-dissociation constant, Ka, for a weak monoprotic acid HA is 2.5x10^-6. The ph of the .4 M HA is closest to?
can someone show me the steps? i am feeling to anxious to think atmD:</p>
<p>If you have resonance with, for example, a single and a double bond, the bond order is actually 1.5 (the average of 1 (single) & 2 (double)) due to resonance.</p>
<p>You could do an ICE table, but for those types of questions it usually ends up being Ka = x^2/[HA], where x = [H+] = [A-]. So 2.5x10^-6 = x^2/.4, solve for x, and do -log(x).</p>
<p>Do we need to know Beer’s Law? I just checked my PR book, and it only briefly mentions it in passing… It doesn’t have anything about a calibration curve.</p>
<p>Anyone have any useful links/sources for stuff about the AP chem labs and equipment and what should be used when?</p>
<p>^ lab equipment would be pretty great to know.
But I remember reading somewhere that there aren’t any lab questions anymore . . .?</p>
<p>What units are used with G and S?</p>
<p>S is J/Kmol.
G is J/mol.
H is kJ/mol.</p>
<hr>
<p>When writing the descriptive equations, and it says “___ metal” (ex. Zinc metal) do you write the oxidation state with it? Like Zn2+ or just leave it as Zn?</p>
<p>I would leave it as Zn (s), because “Zinc metal” implies that it is a solid and not in an aqueous solution so it wouldn’t have a charge.</p>
<p>Good point!</p>
<p>Why is hydrogen phospide PH3 and not H3P?</p>
<p>If it says “metal” it means it is in it’s solid form if it wants the ion then it will say a “solution” of ZnCl2 which is soluble thus giving you Zn2+</p>