<p>Vadata:
I did AB last year and am doing BC this year.
Uhhhhhh I don’t know any of the BC topics, really. Pretty much screwed for those stupid parametric Free-response questions, polars, series, whatever. I know Euler. . . I think.
Anyway I find Chemistry decently easy when compared to Calc BC.
Unfortunately I don’t know a few topics though. . . and I’m going to fail the SAT Chemistry even with this AP knowledge. ._.
self-studying sucks . . . is anyone else self-studying here?</p>
<p>@JohnnyHoppy:
How can it be double bonded on both sides, though?
With the lone pair S has, wouldn’t it mean it has 10 electrons?</p>
<p>I feel prepared, and I feel like I’ll get a five, but I can’t stop studying. I feel like the one thing I don’t cover today will end up being a big portion of the test and I’ll forget how to do it (like when I took a practice AP/my final).</p>
<p>On the Sulfer Dioxide thing again - why does the College Board say (6c)
“the point is NOT earned for a description of resonance as a dynamic process”?
Isn’t that what makes the bonds of equal length?</p>
<p>EDIT: Coffeeandtea - I FEEL THE SAME WAY.
I took the 2002 and 2008 tests and got a 5 easily on both… but then I always think that some random thing I didn’t learn will show up…</p>
<p>^ what do they even mean by a “dynamic” process?</p>
<p>When I did a practice MC I got enough for a 5 (I think I had a ~52 raw, so it’s decently far from a 4 . . . kind of). I’m afraid I’ll screw up the Free-Response though.
Especially if there’s a buffer or some other stuff. Or titration . . .</p>
<p>When buffering, the first horizontal portion is the buffer region, and then the vertical portion is the half-equivalence . . . ? The part where half of it has all been titrated/neutralized?</p>
<p>SuperCuber - you have a copy of the 2008 test?! COULD I HAVE IT PLEASE?</p>
<p>^ Hm.
So there can be a double bonded one, which would violate the octet rule, or the one-double-one-single-onelonepair which would NOT violate it?</p>
<p>Hess’s Law works for dG and dS correct? That is if they give you equations to manipulate to get to cancel out to a certain reaction. I am pretty sure it does but just want to check.</p>
<p>Ok so quick hybridization question… lets take methane for example.
It takes the s block thing and the three p block things, and merges them into one big sp3, right? But if not all of the subshells in an orbital is required (like the 2 spaces in s and 4 in the p) then it’s just an sp2 hybridization with the last part of the former s block unoccupied, correct?</p>
<p>OK PEOPLE - I have a 2002 MC but I wrote on it… still interested?
I’m almost positive you can find it online though. 4khaos I can’t speak for coffeeandtea but I got an 85% and an 87%.</p>