<p>I don’t know, I just read it online that it was . . .
Are both of them negative then? And both of the cathodes are where reduction occurs?</p>
<p>I haven’t taken it either.</p>
<p>lol It’s not like we’ll have the answers with us. When east coast finishes, west coast begins.</p>
<p>According to PR, it says that reduction is always at the cathode. If reduction is at the cathode, then it means that it is positive. However, don’t go by positive or negative. You should go by oxidation and reduction if you get a question…</p>
<p>Okay. So the ONLY difference between galvanics and electrochemicals are the spontaneity?</p>
<p>Does anyone have predictions for FR?</p>
<p>Yep that’s the only difference. </p>
<p>Umm probably not anything they had last year, so no organic, electrochem, acidbase. Maybe a kinects question?</p>
<p>I would LOVE a reaction rate question.</p>
<p>So…exactly 1 hour until I take the test. Any last minute question I could use to review by anyone?</p>
<p>Wrong. Electrolytic cells are not only nonspontaneous, but also have a reverse current. When the poles switch due to the battery (ie positive and negative), the current flips too.</p>
<p>Abrayo, you seem to be good at this. Can you tell me how we would do a question where they ask us something like “What is the initial rate of appearance of (product)?”</p>
<p>Wait skateme, does that mean that the cathode is negative and the anode is positive?</p>
<p>@skateme:
Aha!
So does that mean the cathode is now where oxidation occurs?
What does that mean in terms of cathode/anode?</p>
<p>@Bioboy:
Just look at the given value when t=0!</p>
<hr>
<p>Is NH3 a strong base, and NH4+ a weak acid?</p>
<p>Also, when you form a complex ion, does the subscript go outside of the square brackets or around the ammmonium?
I’ve seen both.</p>
<p>Okay, time to see how I do in this.
Good luck to all you guys.</p>
<p>I recall both to be pretty weak.</p>
<p>No, PR says that reduction is ALWAYS at the cathode, no matter what cell.</p>
<p>Sometimes they don’t give you the value of the product at t=0. Meh whatever, if I have it I’ll just write “This is sparta” and move on xD</p>
<p>And…yes that is correct.</p>
<p>Good luck, JohnnyHoppy!</p>
<p>@BioBoy:
I have never seen a case like that.
Do you remember where you did?</p>
<p>The subscript goes outside.</p>
<p>Chewydog, now that I think of it, you may be right…
because NH3->NH4+OH, but the NH4 dissociates…</p>
<p>Bioboy: yes. </p>
<p>Abrayo: Reduction always occurs at the cathode and oxidation always occurs at the anode. There are no exceptions to this.</p>
<p>NH4+ is a strong conjugate acid. When compared with a strong regular acid, its nothing.</p>
<p>About to leave to go take that test. Good luck everyone. I’ll check back at 7am.</p>
<p>Well I’m about to head out to take my exam. Good luck everyone!</p>