Didn’t it ask for complete electron config? If not, then probably. @nhnct21
@Ninja46 - Yes! They had to be touching. Otherwise it’s not a compound.
@nhnct21 - Yes, abbreviated electron configuration is allowed, as some answers are in abbreviated electron configuration. I don’t see why they would take off.
No, it just asks for electron configuration. And thanks! @chemstar @polarknut
Also the water doesn’t form a compound with the Ca2+, it’s just the attraction of dipole moments isn’t it? So is it necessary for it to touch?
Shouldn’t they be dotted lines?
@nhnct21 - I didn’t have the version, however the picture should look like this whenever one of my classmates asked for the drawing - http://gyazo.com/4e6f088d2b77f18f214af57e2e115416
@chemstar if we didn’t put them touching, is it possible that we can get partial credit if it is worth multiple points?
they dont have to be touching, its an ion-dipole attraction. theres no compound or anything. an example with Na+ http://figures.boundless.com/30062/full/Na%2BH2O.svg.png
@chemstar I’m not sure if that’s necessary though, because I found this diagram on an online source - http://figures.boundless.com/8912/full/ionsinwater.jpe
I think I messed that question up, I put two water molecules oriented around the Ca2+ and then two water molecules off of one of my original water molecules, so I’m not sure if they’ll give that to me.
@zach1198 I think that part is only worth 1 point, because the question is 4 points total, and part (b) is probably the one worth multiple points. I don’t know if they won’t give you the point if you don’t have them touching though.
@zach1198 - I honestly don’t think so because your drawing is showing: Ca+2 + 4H20 as a product. :\
@chemstar you seem to be very knowledgeable about AP exams. So if college board actually made a mistake and didn’t print 2e and 2f on some peoples exams (even though they probably didn’t and we probably made the mistake). What do you think they will do?
Is getting 4-5 parts (some of them being d or e or f) wrong enough to kick you out of the 5 range?
@Tweedle definitely not, if they’re each worth 1-2 points.
dude just do the math.
If you think you need 70% to get a 5:
(x/2) + (y/2) > 70. plug in you mc percentage for x and your free response percentage for y.
@zach1198 - Haha. I know where you’re heading too, but sadly we are all human. It’s fine to make a mistake on a diagram, one point won’t decide whether you’re going to get a 3 or 4, 4 or 5. College Board has many reviewers before they publish an exam and only 2-4 forms are published depending on the subject. Don’t worry about the question, I may not be right, and hopefully they give you the points. But I am just giving my input to what I’ve seen when grading Free Response problems and how strict it can be.
Also for the dissolution of Ca(OH)2 I added H2O on both reactant and product side since it asked for complete equation and not net ionic in pure water?
@Tweedle the dissolution equation is simple: Ca(OH)2 <->Ca2+ + 2 OH-. This is pretty standard stuff.
@chemstar Actually, that’s wrong. The water molecules should NOT be touching the ion, because it’s not like it’s forming a compound, but rather, the ion-dipole attractions are what is attracting the Ca2+ to the H2O molecules.
Sure it’s “standard stuff” but when you’re in a test mode setting and have test anxiety, it’s easy to confuse yourself. Plus since it said in pure water, even though H2O is just a spectator molecule, it’s still there. 
@glasshours Don’t worry! If you put either of the fluoride containing compounds, then you got it right. Any conjugate base will hydrolyze to form a basic solution as shown here: A- + H2O–> HA + OH-
@Tweedle actually, if you check previous ap exams and their answers (check 2012) there is no water present in the dissolution equations given in student samples. Just the compound and the ions, and since it asked for net ionic, you shouldn’t be leaving a SPECTATOR water molecule in there.