Official AP Chemistry Thread (2014-2015)

For 1e, when you remove an electron, isn’t it from 3d because 3d has a higher energy than 4s?

@Zasdil11 no. It is removed from 4s. Although it is true that 3d is of higher energy, 4s is the valence shell. Electrons are removed from VALENCE SHELLS to form ions.

Oops, looks like I got that part wrong. I knew it felt wrong to say that 3d10 was the orbital that the electron would be removed from, but the time constraint just ended up letting me put that :confused:
Anyone have a clue on how to do number 3, the long FRQ with the titrations? I’m stoked on that one.

@Mochis1 i know how to do it. PM me, and we can talk about it.

@michelle426 why don’t you just post the whole answer here!

@baller55 I’m currently at a math session. I’ll post the basics of the answers here later.

Perfect!

@Mochis1 it’s easy to think about it this way: Zn is oxidized generally in a +2 charge bc it loses the 2 4s electrons. When contemplating a (n-1)d orbital and a ns orbital order of fill and loss, the ns orbital will fill first and lose first. :slight_smile:

are we ever allowed to speak about the multiple choice?

Technically we can’t since CollegeBoard said to “never speak of it”, but everyone does anyway. So basically we can at our own risk.
Was I the only one that thought that the MC was kinda difficult? I mean, I think I got at least half of them, but the other half was either meh or I don’t remember/know it.

Where the heck was the elusive questions that people skipped over?

@Kylemcgrogan yeah like 104.5 but based on past frq score guidelines they’ll accept 109.5 or 109 because it comes from tetrahedral or they’ll even take an answer like greater than 90 and less than 120

Yea I thought it was fairly difficult. There weren’t more than 15 where you could answer with certainty. It was all narrowing it down to 2-3 answers and making a somewhat educated guess. I hated that test. Not a good indicator of how much chem one knows. A great indicator of how successful one is with the guessing game though

My test was exactly like what they released!!!

  1. Titrations:

a) Net ionic: C6H7O2- + H+ <-> HC6H7O2

b) (29.95 / 1000) (1.25) = M2 (45 / 1000)
M2 = .832

c) Thymol Blue: Use Henderson Hasselbach for when the indicator disassociates. ph = pka + log(base/Acid). We want this ph to be closest to 2.54; 2 is the closest. More specifically, most indicators change color when ratio of base to acid (or acid to base) is 1:10. Therefore, 2 +/- 1 gives the closest range that includes 2.54.

d) ph at half equivalence point = pka = - log (1.7 x 10 ^-5) = 4.77.

e) Curve’s a bit odd, because it doesnt seem to fit the usual weak base strong acid titration curve, but use the three points you have and simply plot it as best as possible.

f) Henderson Hasselbach again: 3.37 = pka + log(C6H7O2 / HC6H7O2). pka = 4.77, so
log(C6H7O2 / HC6H7O2) = -1.4. So 10^-1.4 = C6H7O2 / HC6H7O2

Therefore, since C6H7O2 / HC6H7O2 < 1, We know that HC6H7O2 has the higher concentration.

This was actually much simpler for acid bases than i was expecting.

**This is all based off of memory, some small things may be off.

@nhnct21 I think you’re right. If you didn’t see them there initially and weren’t looking for questions beyond the first page for each, anyone could have easily missed them. It’s highly unlikely that some were miss-printed. All the ones that people claim to be missing were at that same right top spot, which means people just didn’t see them. All released practice exams were like that, so I didn’t miss them , but I could see how people would. Bad spacing on CB’s part? Yeah. Their fault, though? Nah.

I got the same answers for #3 Titration. And hopefully they’ll give the point for 109, cause that’s what I put :’)

@eeqeqqe for part e in the titration how did you find the volume of acid added at the half equivalence point to plot the point?

@eeqeqqe

I agreed with you all the way until the last part. How wrong am I for justifying that there would be more HC6H7O2 because the strong conjugate base, C6H7O2-, would attract any of the H+ ions in the already acidic soda?

The PH for the halfway point cannot be 4.77 if it is a weak base strong acid titration
http://www.fccj.us/chm2046/SampleTest/46M12dAnswer.htm