Official Dec 2012 SCIENCE thread

<p>Really easyyyy compared to last time</p>

<p>Agreed.</p>

<p>Sent from my DROID RAZR using CC</p>

<p>I made a really stupid mistake, however. At the last second, I changed one of my answers from ‘balance’ to ‘hydrometer’ like an idiot…</p>

<p>What did you guys put for the question asking why the physicists dropped the balls from the location they did? </p>

<p>Was it to lessen the effect of gravity?</p>

<p>I felt it was really easy compared to last time’s science. But I have a question…
you know in the titration passage, the first question was to like choose the picture that is described for the titrant? which one was it? was it for the titrant or the analyte?</p>

<p>I chose the one for the tiltrant. It was a narrow tube with a nozzle at the bottom.</p>

<p>Dammit…i chose the beaker.</p>

<p>i think it was a tube with the rubber on the bottom</p>

<p>So glad i took ap chem!! It definitly is the one on the bottom left. The buret heres a pic <a href=“http://ecx.images-amazon.com/images/I/21EIV4xWocL._SL500_AA300_.jpg[/url]”>http://ecx.images-amazon.com/images/I/21EIV4xWocL._SL500_AA300_.jpg&lt;/a&gt;. Didnt really get to the last one, how many B’s for the last passage??</p>

<p>Ok on the same titration passage, i think it was the second to last question or it might be the last question, dont remember. but it said something like, a scientist thought the acid tested in figure 1 was pyruvic acid, which as a pKa of 2.5 . Which of the following proves this statement to be incorrect?</p>

<p>Damn it. I chose the test tube. I almost went for the tube with the rubber on the bottom, but then I was like, “No, that can’t be it, it’s too different.” Curse my logic.</p>

<p>I chose the one with the nozzle on the bottom too. What what the answer to the one about how much higher the stell ball would bounce if dropped from 2m?</p>

<p>@nivers i don’t remember exactly but I think I said something about how the half way point wouldve been more? Idk though, i don’t remember my answer but i seem to remember ring confident in it haha</p>

<p>@Linz25 I put 0.5 increase but really didn’t have much idea what it was talking about…sort of logic’ed that one out.</p>

<p>I put .5 increase cuz i plugged in values into the equation that was provided in the passage.</p>

<p>pretty sure it was .50
c=y/h
.65=y/2
.42=y/2</p>

<p>1.3
.84</p>

<p>1.3-.84 = about 5</p>

<p>Andrew, i did the exact same thing. I looked at the data and even though it was only a .2 increase, .5 is closer to .2 than 1 is so yeah…</p>

<p>@Linz25 I said that it would decrease by 1m.</p>

<p>There was a table with the different bounce height percentages in the two different environments, you had to look to that to see that the bounce height of the metal ball was .55</p>

<p>Ball being stuck would be 0.</p>

<p>Yes! 0.5 increase was right!! My guessing is too clutch!</p>