<p>dang it xerian you might have been right, i didn’t look at it closely</p>
<p>did you graph look like this?
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<p>julina- f(x/2) first you plug in a to solve for f(a/2) then you get the answer for f(a/2) so you plug it back in f(x/2) for f(a/2/2) which is just f(a/4)</p>
<p>this is how you do #50 right?</p>
<p>i hope it is</p>
<p>yeah the graph one was definitly II and III</p>
<p>Yeah, that looks like the graph, assuming you remember the right equations. Can you run a calculate minimum on those?</p>
<p>Or was there a domain restriction? That would’ve changed the answer…</p>
<p>I think that’s how you do 50, I just didn’t have time to finish it . . . got to the f(a/2/2) part but didn’t finish the computation</p>
<p>Are you sure you’re allowed to be talking about this?</p>
<p>xerian ther was no domain restrction</p>
<p>i just remember it was like f(x)=x^4+x^2+c and then the other equation was f(x+2)</p>
<p>i forgot the specific equation</p>
<p>the minimums LOOKED the same, but who knows</p>
<p>The only time I’ve ever heard of restrictions about talking about questions after the test was for the AP exam</p>
<p>Hey…for the one where it asked if y was a function of x, number III’s eqn would have been just y = 1/2, and therefore y is not a function of x - so the answer would have been just II. </p>
<p>That was my reasoning…but I wasn’t too confident and left it blank anyways.</p>
<p>Was the first one not a function?</p>
<p>it is II and III…I used 89</p>
<p>Yeah, I was wrong. Logic would’ve prevailed where the calculator failed.</p>
<p>orchdork - true that y=1/2, but the like y=1/2 is a function, so both II and III were right</p>
<p>xerian- yea, first wasn’t a function</p>
<p>dorisz- which one are you referring to? the one with the 2 graphs or the y is a function of x</p>
<p>Oh yeah… I should’ve looked for repeated Y-values. I feel stupid. So That’s 4 skipped and 2 wrong… I’m doomed.</p>
<p>these 2 were near the beginning:</p>
<p>find the parallel line that includes the origin</p>
<p>was that A, 2x-y=0?</p>
<p>and was one of them tan66degrees, C</p>
<p>billybobby- do you remember the wording for #49? anyone remember the wording for #49?</p>
<h1>49 - 4x^2+3y^2=16 is same as x^2/a+y^2/b=1</h1>
<p>I thought the circle translation was 5 to right and 3 down…Wasn’t the original circle center 3, -1?</p>
<p>doppelganger-the circle one moving 5 to the right and 2 down for (x-3)^2+(y+1)^2=25
the answer would be (x-8)^2+(y+3)^2=25
because the center before the translation is (3, -1) and in the second one the center is (8, -3) which is a shift of 5 right and 2 down.
i think i did ok hopefully i got 750+
i left 4 blank and guessed on 2 and as far as i know got one wrong…</p>
<p>and did #49 ask for the values of a and b??</p>
<p>So the new eq would been (x-8)^2 + (y+3)^2 = 1, right? Yes, 49 asked for both a and b.</p>
