<p>i dont remember the exact answer, but i know it was D</p>
<p>x-8 y-1 was just a guess</p>
<p>what the hell r u taking bout asain</p>
<p>i was talking to the loosers who are too afraid to discuss the test</p>
<p>sthaznpride17 </p>
<p>dk for the first one i took the inverse sin of that number, multiplied it by 4, and took the sin of the 4 x number. </p>
<p>wouldnt that be 4sinx, not sin4x? i did what you did at first but then changed it last minute</p>
<p>hmm… thats not what i got for the pqr one… anyone else get i think (pqr)^9???</p>
<p>dk333 i think he was talking about what you did</p>
<p>for ex:
sinx=.56
inverse is 34.06
then 4x34.06=136.22</p>
<p>and then sin(136.22)=0.692</p>
<p>assuming that was the question though i think it’s not</p>
<p>so did anyone get p^3q^6r^9 for #48 the prime numbers one?</p>
<p>For the pqr one I got something like p^5q^15r^21. Something like that, but I wasn’t too sure of the answer.</p>
<p>I skipped 8 questions. I hope the curve is REALLY favorable (I’m shooting for ~700) :(</p>
<p>i dont remembr there beting about the inverse for that problem</p>
<p>nooo i got like p3q15 andr18 i think?</p>
<p>hey dudes on that second to last one did you get a=2 b=4/squareroot of 3 ?</p>
<p>yea billy you’re right</p>
<p>did anyone get II. intersect at exactly 1 pt and III. same range for like #37 or 38 or so</p>
<p>ya i got that</p>
<p>How did you do number 50?</p>
<p>if you graphed them, you’d see that they both have the same minimum y value and rise both left and right so the range is (x,infinity) for both, with x being w/e the lowest y value was</p>
<p>julina- first you find f(a/2)=RAD(1+0/2) = RAD0.5 = 0.7071
then f(a/2/2)=f(a/4)=RAD(1+.7071/2)=0.934 or so</p>
<p>was the combinations one 1/6? 3c1, 2c1, then 1c1, so 3<em>2</em>1=6 right?
i hurried through that one</p>
<p>I graphed them and saw diff Ymin values. Must’ve made a stupid mistake.</p>
<p>yeah 1/6 .</p>
<p>How do you to do f(a/2/2)? I’m so confused…</p>
<p>aznosamaboy - Yeah, the combinations one was 1/6 (1/3 to get one out of three balls, times 1/2 to get one out of two balls, times 1 to get one out of one ball).</p>
<p>juliana- you just do the operation twice, plugging in your 1st answer as f(a)</p>
<p>Its more problems that talk about possible combinations of things that give me trouble - probability has always been my weak point. And computation. Thank god for calculators.</p>
<p>Do you remember the exact wording for 50? How do know to do it twice?</p>