Official thread october sat 2013 test

<p>@jugujeegee
I had that one, but Idk if that one’s the experimental or not.</p>

<p>What was the perimeter question(for the one with the x=1 and y=2 thing)? 6?</p>

<p>Coassack, that doesn’t sound good for me :frowning: Did you have an experimental math section? I’m 95% sure I did.
Though as much as I’d like to have brought up my math score, I’m really just hoping to bring up my critical reading score as it’s the only one in the 600s.</p>

<p>Jugujeegee that was no error</p>

<p>Why sin’t before finally wrong? Shouldn’t it be either before or finally??</p>

<p>@jsjang</p>

<p>it was not experimental.</p>

<p>I know for sure my experimental was math since I had 2 grid-in sections.
And so if I had that writing, it cannot have been experimental.</p>

<p>Is there a consensus on the parallelogram with another inside it, and the trisected diagonal? I put 1/3.</p>

<p>yes the perimeter was 6</p>

<p>Yea I put 1/3 for the parallelogram</p>

<p>Theres nothing wrong with before finally</p>

<p>Saratoga, I’m pretty sure I got a CR experimental. But yeah, I only omitted two and I know I got two wrong so far, but the rest was basic algebra and geometry.</p>

<p>@jugujeegee
Was that one the one including sanskrit and the Mayans?</p>

<p>I also answered 1/3 for the parallelogram.</p>

<p>@jsjang</p>

<p>Yep. I had an improving sentences question on sanskrit.</p>

<p>Cossack, I’m pretty sure the math section I think I failed was an experimental (at least I hope). I omitted 3 on that one. Other than that, now that I think about it, the math WAS pretty easy; it was just the one math section that freaked me out.</p>

<p>Nope, before finally made the sentence parallel</p>

<p>@jlee</p>

<p>The median question was m=r.</p>

<p>We wish to show that the median and the range in the second set are equal.</p>

<p>Let S be a set of 15 positive integers such that the range of S, denoted by r<em>s, is equal to the median of S, denoted by m</em>s. That is,</p>

<p>(1) r<em>s=m</em>s.</p>

<p>Let a and b be the smallest and greatest members of S, respectively. Note,</p>

<p>r_s=a-b.</p>

<p>By (1) we have,</p>

<p>r<em>s=m</em>s=a-b.</p>

<p>Now let the set T consist of all the members of S multiplied by 4. Denote the range of T by r<em>t and the median of T by m</em>t. Note that</p>

<p>r<em>t=4a-4b=4(a-b)=4(r</em>s)=4(m_s).</p>

<p>But, by our operation to create set T, the element in T corresponding to m<em>s is 4m</em>s. Note that if a number is the median of a set, and all element of that set are multiplied by a constant, then that number multiplied by that constant is the median of the new set.</p>

<p>Thus,</p>

<p>r<em>t=4(m</em>s)=m_t</p>

<p>QED.</p>

<p>Alternatively, if you don’t want to read through my proof you can see the error in your solution if you look closely enough at the least step. You mixed your numbers up.</p>

<p>I realize this isn’t the first thing that most of us think about when testing, but do you guys who are worried sick about which section was experimental and which wasn’t keep tally of the number of sections you’ve already done for each component? I knew by the time section 8 rolled around that I had the writing exp. sect.</p>

<p>Saratoga, you had a math experimental where the last question was 3^20002/(5+3^20000) huh. </p>

<p>That section had a couple tricky sections, but I think I aced it even though it was experimental.</p>

<p>I thought the first CR section was difficult, not sure why.</p>

<p>for the median and range, you can use 1,1,1,1,1,1,1,2,3,3,3,3,3,3,3.
m=r.
consolidated list of answers, anyone?</p>