<p><a href=“Supporting Students from Day One to Exam Day – AP Central | College Board”>Supporting Students from Day One to Exam Day – AP Central | College Board; Go to page 13, the (c) and (d) part. Do you suppose to get 2.42V and 4.5<em>10^-25 kg</em>m/s? I’m utterly confused by this problem.</p>
<p>c) Convert KEmax into eV. Drop the e and write the number in volts. I think it was around .6 or .7</p>
<p>d) KEmax=(1/2)mv^2. m and KEmax are given. Solve for v.</p>
<p>ok… Can anyone actually work it out see if they get 2.42V and 4.5<em>10^-25 kg</em>m/s?</p>