Perplexing Math Problem. Help Please!

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<p>^ Can someone explain the question in example 2 from this page? Thanks!</p>

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<p>In order for segment PC to intersect line L, points P and C must be on opposite sides of line L.</p>

<p>In this case, that means that point P must me placed to the left of line L on segment AB.</p>

<p>Segment AB is 2 units long. Segment BC is 3 units long. So segment AC is 5 units long.</p>

<p>Point P has a 2/5 chance to be placed on segment AB.</p>

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<p>Thank you for the explanation, manarius! :)</p>

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<p>Glad to help</p>