<p>Compute the probability of Kevin getting into Princeton given that:
[ul]
[<em>]SAT: 2300
[</em>]3x800s on SATII
[li]valedictorian[/li][/ul]
Please express your answer as a reduced fraction.</p>
<p>Sheep, you would first have to fix the lowish GPA, then raise CR to a 760+, then explain away the screwed AI because of the small school and extra time for tests, if that is the case.</p>
<p>Your probability is: 1/n where n is a real number.</p>
<p>No, buddy, you have to express your answer as a Riemann Sum for this college. Geez, what is this, Cal State Fullerton?</p>
<p>
Where n is a real number greater than or equal to 1, you mean? His chances certainly aren’t 1/0, and I’d be very surprised if they’re 1/-5 or 1/.42.</p>
<p>No chance at all… Only Zimbabwe State school- yet, it is a reach. </p>
<p>I mean how dare you ask to chance yourself for Princeton on the basis of stats. More than half of Princeton applicants (exaggeration) have that range of SAT I and II scores plus Valedictorian status.</p>
<p>You need to do a little work in order to determine your chances.</p>
<p>I’d say you have a e^(2(the sum of the reciprocals of perfect squares from 1 to infinity))% chance of getting in. Iff you know what the exact sum of the reciprocals of squares is off the top of your head.
If you don’t, you can halve your chances.</p>
<p>OR, if you can give an exact closed form evaluation of the infinite sum of the reciprocals of perfect cubes, your chances skyrocket to the limit of sin(x)/x as x approaches 0.
I doubt you can, though.</p>
<p>You can raise your chances to the definite integral of -ln(x)/(1+x^2) from x=0 to x=1 by killing the ■■■■■ that is orcaaa, too. Your chances are practically 1 iff you can manually give a closed form expression of that indefinite integral.</p>
<p>Absolutely no chance whatsoever. I’m surprised you haven’t dropped out of high school already and started a career with your local fast food joint.</p>
<p>2/5 or 3/7.</p>
<p>This is one of the most interesting conversations I have read 4 a while :D</p>
<p>@ clandarkfire
<3 ur answer! If kevin gets that, then he has a GOOD shot.</p>
<p>Let Kevin’s chance at Princeton be represented by Y. Then Kevin has a chance of</p>
<p>Y =[ [(SAT + SATII)/2]e^(x/RANK)) / 26247(z^2) ]*random rational number between 0.01 to 1.99</p>
<p>Where z = number of standard deviations Kevin is from the 3rd standard deviation above the mean applicant and x is given by: a/10 + b/5 +c/2 +d, where a, b, c, and d are number of extracurricular activities that are at school, state, national, and international levels respectively, and the random rational number accounts for all the other unpredictable variables.</p>
<p>Substitute in Kevin’s given values, and logically deducing that kevin’s z value = 3</p>
<p>Y = (2350e^x)/(26427*9) rand#(0.01-1.99)
Y = 0.009881(e^x)rand#(0.01-1.99)</p>
<p>:P</p>
<p>Thanks to rkanan and clandarkfire, I’m convinced I’m not getting into Princeton now :’(</p>
<p>;)</p>