PSAT math question (Kaplan 240)

<p>AA + BA = 1B8</p>

<p>I struggle with problems like these–please help!</p>

<p>At least one solution: A = 9, B = 0;
99 + 09 = 108 or … </p>

<p>Solution method.
A + A = 8, or 18 (it cannot be 28 or greater…)
If A =4, then B = 6, 7, 8 or 9
but you can quickly see that none of these work. </p>

<p>If A = 9, then 99 + B9 = ?
For <em>any</em> B (0,1,2,3,4,5,6,7,8 or 9) it comes out correct.</p>

<p>Don’t practice with non-college board tests!</p>

<p>Rewrite problem as 10A + A + 10B + A = 100 + 10B + 8 (this is often a good strategy for digit problems)</p>

<p><==> 12A + 10B = 10B + 108
<==> 12A = 108
<==> A = 9</p>

<p>Any solution with A=9 and B = 0,1,…,9 works.</p>