<p>how do you calculate the intersection point between a circle and a line</p>
<p>please keep it ASAP (as simple as possible) :D</p>
<p>use the perpendicular distance between line and point formula. take the line you want, and set the point as the origin. that distance should be the radius of the circle…so that line and x^2+y^2=(distance you got)^2 should be the 2 equations that are tangent at 1 point</p>
<p>not sure if that’s right but thats the explanation barrons uses</p>
<p>easier said than done…ill just leave it in blank tomorrow if I get any</p>
<p>Im just not going to get it in the next 5 minutes, and I have to go to bed…</p>
<p>Use your graphing calculator…?
graph the equation of the circle in y1 and y2, the line in y3. Use 2nd->calc->intersection.</p>
<p>^ How do you do that on a TI-89? There’s no CALC button.</p>
<p>lol, it’s f5 instead, while you’re in the graph window, math>intersection</p>
<p>other useless things in there include min and max</p>
<p>I’m going to go and take a practice test for tomorrow morning… it’ll be my last one ever :p</p>