<p>Could someone help me understand today’s question of the day?</p>
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<p>I don’t understand how (a/b)=3 becomes (a+b)/(b)=4</p>
<p>There’s already another thread about this…but anyway it’s just a trivial question about plugging in numbers. Don’t worry about the algebraic way.</p>
<p>If a/b=3, then A=3 and B=1, so (A+B)/B is 4. It works with any ratio that equals three; 6/2=3, (6+2)/2=4.</p>
<p>Does that help?</p>
<p>Ah…yes that does make more sense now. Thanks!</p>
<p>Their explnation us stupid… If u solve a/b=3 and b/c=7 into a= 3b and b= 7c respectively… Then add b so that a+b=4b and add c so that b+c=8c… Then u have a+b/b+c=4b/8c so that equals (b/c)x(1/2) and u have what b/c equals… And i think u can solve from there</p>
<p>cheap solution:
Assume that b=7, we then know that a=21 and therefore c=1, thus the answer is 7/2</p>
<p>a=3b, b=7c.
3b=21c=a</p>
<p>(21c+7c)/(7c+c)=28c/8c</p>
<p>c’s cancel out, simplify and it equals 7/2</p>