<p>If the girls who bought turkey sandwiches have $206 in total to spend
on their lunches,what is the greatest number of turkey sandwiches
with fries they could buy without exceeding their budget ?</p>
<p>1)23
2)24
3)25
4)26
5)27</p>
<p>Hi I was able to solve this by substituting numbers,but how can I solve this algebraically ?
I got the answer D</p>
<p>I solved it this way.
4.5x + 26(5.50) = 206.</p>
<p>Other number I got decimals,which illogical because you can’t have decimal sandwiches,but how can I solve this question using algebra in-case if it comes in grade in questions.</p>
<p>GenericMath, you need to specify the given information completely. </p>
<p>Does your book tell you anything about the total sandwiches that the girls buy?</p>
<p>If not, the answer should be 37 sandwiches with fries that the girls can afford to buy with $206. (206/5.5 = 37.whatever). Since 37 is not one of choices, there must be an additional condition on the number of sandwiches.</p>
<p>The only thing worse than using McGraw Hill horrible book is paraphrasing the questions. In this case, there are two tables and two related questions. Your question also relates to the tables printed above it. </p>
<p>The girls bought 40 turkey sandwiches in total.</p>
<p>Your answer 4.5x + 26(5.50) = 206 should be</p>
<p>Fwiw, there is a shorter way to solve this problem but it requires understanding variable ratios. I’ll offer it but you should probably stick to the algebra. </p>
<p>Anyhow, here it is.</p>
<p>Average cost of sandwiches = (4.5 + 5.5)/2 = 5
Cost of 40 sandwiches = 200
If sandwiches were equally divided = 20 of each </p>
<p>Since you have 6 extra dollars and the difference in price is 1 dollars, you could have 6 more of the expensive and 6 fewer of the cheap one. Hence:</p>
<p>20 + 6 = 26 with fries
20 - 6 = 14 without fries.</p>
<p>@xigi why Mcgraw hills has some interesting questions and some hard ones aswell that it would be good to add to database of ideas for sat math questions.</p>
<p>@Knowthestuff,ApManiac.</p>
<p>I just copied the question as it said,but what I understood from the question is she buys both a sandwich with fries and a sandwich without fries.</p>
<p>The turkey sandwich without fries cost 4.50$ and sandwich with fries cost 5.50 $.</p>
<p>So then I substituted values like this 4.5x + 26(5.50) = 206 this is the only one which gave an output of non-decimal values for 4.5x other values gave decimal output,so in logic we can’t have a decimal sandwich it must be a whole number.</p>
<p>I was wondering though how can we do this algebraically without resorting to substitution? In case if this type of question comes in grade in because I saw this type of question before in a grade in.</p>
<p>Generic, the most important lesson for the SAT is to PAY CLOSE attention to the instructions. Your question was related to the tables before Q5 and Q6. You missed the total number of sandwiches. </p>
<p>There is NO need to substitute numbers. But that becomes a broken record here! :)</p>
<p>Even though I solved question 5 right and used that information I didn’t really notice it for question 6. Need to pay attention 100 % for solving for SAT!!!.</p>
<p>Or just start by assuming all 40 were at $4.50…which comes to $180, leaving an extra $26 so you have enough to upgrade 26 orders to include fries.</p>
<p>And yet again a problem that seems to require simultaneous equations yields to read, think, play …</p>